At t=2, your acceleration will be the same as on RE. IT'S THAT SIMPLE. NOTHING IS CHANGED EXCEPT THE METHOD IN WHICH GRAVITATION WORKS. Terminal velocity will be the same. Everything will be the same. STFU, GTFO.
no it will not calculate the acceleration on the object and you will see that it is not the same
Okay, let's take this one step at a time.
On FE:
1. You drop an object.
2. The Earth begins to accelerate towards the object, pushing air with it.
3. Though the object initially had an acceleration of 0 m/s
2, it will now begin to accelerate due to air resistance.
4. The object reaches 9.8 m/s
2. It is now going a constant speed.
Now, this conforms exactly with the equivalence principle. The only thing changed in this scenario compared to RE is our perspective.
On RE:
1. You drop an object.
2. The object begins to accelerate at 9.8 m/s
2 towards the Earth.
3. As it encounters air, friction builds until the object begins to decelerate.
4. The object now has an acceleration of 0 m/s
2 and is going a constant speed.
Besides our perspective, there is NOTHING different between the two scenarios.
Now I ask you, what IN THE WORLD would change the acceleration or anything between the two scenarios?
no it will not calculate the acceleration on the object and you will see that it is not the same
Then you have just proved the EP to be incorrect. Congratulations. Arguing the exact same point with you page after page, even though numerous other independent posters have shown you to be wrong is getting very old. And annoying.
the EP can only be applied after it reaches 9.81 m/s/s not before
WTF?