As stated before:ae - ao = 0 (1)ao = vt/t (by definition) (2)ae - vt/t =0 (3)t = vt/ae (4)t = (22.1426m/s)/(9.8 m/s2) (5)t = 2.26 s
Quote from: Robbyj on August 23, 2008, 07:54:50 PMI am assuming you are going to tell me...No I am asking you if there are any other forces before we move on to the next step
I am assuming you are going to tell me...
Why justify an illegitimate attack with a legitimate response?
Quote from: cbarnett97 on August 23, 2008, 07:59:10 PMQuote from: Robbyj on August 23, 2008, 07:54:50 PMI am assuming you are going to tell me...No I am asking you if there are any other forces before we move on to the next stepNot in the equation I used, no.
Quote from: TheEngineer on August 23, 2008, 08:01:25 PMAs stated before:ae - ao = 0 (1)ao = vt/t (by definition) (2)ae - vt/t =0 (3)t = vt/ae (4)t = (22.1426m/s)/(9.8 m/s2) (5)t = 2.26 sgo read wiki some more, grownups are talking
So you can't fault my argument? Figures. Go back to eighth grade, kid.
I wasn't talking about t=2, I was talking about t=2.26 which =(9.8+9.8+9.8(.26)) which when squared and multiplied by .02 gives you 9.81.
My calculations were based on the FE model and my derived equations.
Quote from: TheEngineer on August 23, 2008, 08:20:07 PMMy calculations were based on the FE model and my derived equations.Well then your failure is complete
There is a terminal velocity. Once Anet=0 the relative velocity will be constant which is the same as terminal velocity.
Quote from: cbarnett97 on August 23, 2008, 08:22:15 PMQuote from: TheEngineer on August 23, 2008, 08:20:07 PMMy calculations were based on the FE model and my derived equations.Well then your failure is completeYet, you can't dispute my equations. So the failure must be yours. But I am sure you are used to that.
Have they been shown to be so? I don't remember them being shown so. Perhaps you can quote the post in which this showing took place? Because, as far as I can tell, my equations have been shown to be correct for the FE.
Quote from: Robbyj on August 23, 2008, 08:26:16 PMThere is a terminal velocity. Once Anet=0 the relative velocity will be constant which is the same as terminal velocity.Yes but how you get to that number is different and that is the difference between the 2 models
Quote from: cbarnett97 on August 23, 2008, 10:46:26 PMQuote from: Robbyj on August 23, 2008, 08:26:16 PMThere is a terminal velocity. Once Anet=0 the relative velocity will be constant which is the same as terminal velocity.Yes but how you get to that number is different and that is the difference between the 2 modelsI used the same equation you did.
so acceleration caused by gravity is the equivalent to acceleration caused by air, wow that is new to me
Quote from: cbarnett97 on August 23, 2008, 10:56:34 PMso acceleration caused by gravity is the equivalent to acceleration caused by air, wow that is new to meEqual, yes. No wonder you have failed so badly in this thread...
It's no slur if it's fact.
Now where did your square root come from?
Quote from: Robbyj on August 23, 2008, 11:09:52 PMNow where did your square root come from?disregard the square root but everything else is correct
All truth passes through three stages. First, it is ridiculed. Second, it is violently opposed. Third, it is accepted as being self-evident.