Oh heaven forbid. You did not understand a word I said. I never said Special Relativity was about gravitation. I said that the limit to Special Relativity before General Relativity was his theory on Gravitation, but he linked Gravitation and Special Relativity with his theory on General Relativity
You're black hole analysis is not what I hope for, far too brief. I'll post my actual report within the next couple of days, I'm off to visit my parents in about half an hour. I expected something of the following length at least.
Commoners? I used Force with inverted commors to suggest that it is a psuedo force for god sake son. How many times do I have to explain this. DO you know what Pseudo means? maybe go look it up in a dictionary now. Oh god you are so stupid I'm not going to continue with this pointless banter
"because the psuedo Newtonian Gravity is simply caused by objects falling towards the centre of mass of heavier objects (and the heavier objects have a much slighter pull towards the lighter ones)."
simply caused by objects with mass that "fall toward each other" or "pulled together"
How does mass cause the curvature of space time?
Again I have to explain it to you but this should suffice, I hope you can understand that it is a fundamental description of the universe. No-one knows exactly why it happens, thats why they are developing theories such as Quantum Gravity and Loop Quantum Gravity, M-Theory, String Theory etc. This is to explain gravity on a MORE funamental Quantum level. However due to its fundamental nature i.e. "Mass creating a curvature in space-time is a fundamental property of the universe" by Einstein's theory there is no direct explanation to why this happens. General relativity explains the actions of objects and light within the universe through the fundamental obervation that mass curves space-time. This observation is backed up by much experimental evidence. The observed curvature is also explained mathematically through Einstein's 10 field equations which have the general form:
R[xy] - 1/2 * R*g[xy] = T[xy]8*pi*G/(c^4)
Where R[xy] is the Ricci tensor, a vector which describes the relationship between Riemannian metric [this is a type of differential associated with the geomtry of the spacial curvature] and classical space.
R is the Ricci scalar, which is a simple determinant for the volumetric changes of the curvature. Simply put, a positive ricci scalar suggests that a small sphere within the area influenced of the curvature will have a different (smaller) volume. It's position is not defined within the curvature...This is taking so long. I'm not going to bother with the rest of the field queation you can look them up yourself. Just know that g[xy] is the metric tensor, the Reimann value describing the actual space time curvature. T[xy] is the stress to energy tensor (a mathematical matrix description for the gravitational source of the curvature), pi is archimedes constant, G the gravitational constant and c the speed of light. I'll now get to what I think you wanted to know.
I think the question you really wanted to ask was "How does space time curvature work"; given the fundamental property that mass curves space time. We know that light always wants to travel in a straight line, and that the shortest path between two points (in terms of distance) is a straight line. However, given that space time can curve, the path the object or light must follow, the curvature of space-time as it is the shortest possible path to follow. This is called a geodesic pathway. If you think of the curvature of space-time as the Spherical Earth, assuming you can not go underground the shortest point between the North and South Poles is a semi circle around it. For objects moving through the space-time continiuum will always move in a straight line. When they reach a gravitational curvature they will continue to move in a straight line, but to inertial frames of reference, that motion appears to be curved.
Because in Einstein's theories we exist in a universe of 4 dimensions and not three, the curvature of of space-time obviously effects both space (x,y,z) and time (t). Consider a a pulse of light from an origin o. Observers standing at o would see that pulse emit as a spherical shell. If we consider the event on a two dimensional level, as the fabric of space time is often represented, with the light emitting in a circle. If we define the z-axis to represent time, we would see that the light would emit in he shape of a cone. In 4 dimensional space-time a hyper-cone would form.
If space and time are one in the same, and a curvature of space-time effects "space" how doesit effect "time"?
We know from experiments that gravitational fields create time dilations. We also know that s one accelerates toward the speed of light, time dilates, as stated in special relativity and proven via experimentation with atomic clocks on jets. Time dialation in gravitational fields is made manifest by the existance of the equivalence principle, i.e. that the notion of gravity, and acceleration are one in the same. We know this because lets say, someone inside a rocket accelerating in free space at g would feel the same downward pull as someone standing on the surface of the Earth. This means that someone accelerating toward the speed of light experiences the same time dilation as someone standing within a gravitational field (as seen by an inertial observer). The greater the gravitational potential (more acceleration due to gravity) the greater the dilation.
I hope my understanding of general relativity meets your community college standards
Don't bother breaking down the above text one sentance at a time, it just shows how stupid you are, people write things as a whole, no one sentance is not mutually exclusie of the greater whole, so if you want to comment just discuss any problems in the above "singular text" method.