An experiment to disprove FET

Engineer: The acceleration is too small to make a significant difference over the timescales in question. At 100,000m/s i'm not going to bother calculating an extra 10m/s over 1/10,000 th of a second am I?

I'll say it again:  Your method of calculating the answer is incorrect.  The velocity of the Earth is irrelevant.  Only the acceleration is relevant.

lol. With you now. *slaps himself*

Socrates' result still stands, however.

lol. With you now. *slaps himself*

Socrates' result still stands, however.

....No it doesn't lol.
The Engineer is right, the light from the boat could be admitted from any angle coming off the boat, and I only calculated the possibilty of the light being emitted horizontally at 0 degrees. But if the ray of light was emitted at 45 degrees it might still make it to the observer.

Eh, I'm too lazy to do that many calculations for now.

Point a laser out the side of the boat. You'd have a check on the angle of light that way.

You'd need g to be a helluva lot bigger to see light emitted at 45 degrees. Your view would be really weird. I'm guessing it'd look like you were standing on top of a massive Redshifted hyperbola.

Point a laser out the side of the boat. You'd have a check on the angle of light that way.

You'd need g to be a helluva lot bigger to see light emitted at 45 degrees. Your view would be really weird. I'm guessing it'd look like you were standing on top of a massive Redshifted hyperbola.

45 degrees was just an example, maybe a more realistic one would be 10 or 15 degrees.

Quote from: Brennan on August 15, 2007, 12:49:24 PM

Point a laser out the side of the boat. You'd have a check on the angle of light that way.

You'd need g to be a helluva lot bigger to see light emitted at 45 degrees. Your view would be really weird. I'm guessing it'd look like you were standing on top of a massive Redshifted hyperbola.

45 degrees was just an example, maybe a more realistic one would be 10 or 15 degrees.

Sorry, but I don't see how the angle effects the math, except maybe to reduce the "effective" horizontal speed of light.

Quote from: Brennan on August 15, 2007, 11:55:33 AM

lol. With you now. *slaps himself*

Socrates' result still stands, however.

....No it doesn't lol.
The Engineer is right, the light from the boat could be admitted from any angle coming off the boat, and I only calculated the possibilty of the light being emitted horizontally at 0 degrees.

Actually, I think that was me who pointed that out.

Quote from: socrates on August 13, 2007, 07:36:50 PM

I tried to figure out how far away the boat had to be to lose 1m of it's image.
Okay this is my math:
*snip math*

The problem with this whole argument is that it only considers light rays emitted horizontally. Some light rays are also emitted up at an angle, so that they bend down as the earth accelerates and still hit the observer. Quite simply, at no distance can acceleration of the earth cause all the light emitted from a distant object to be blocked by the ground without an intervening object in between - the light curves down, so actually distant objects will appear higher rather than lower, as the light observed to be coming from them is emitted up at an angle and then curves down so that it reaches the observers eye coming down at an angle.

Os course, the acceleration is too small compared to the speed of light to make any difference anyways. But my point is that even if the effect were large enough to be significant, it would still be in the wrong direction to explain the horizon.

My bad.

G for Gulliver!! What do I win?

A retry.

Am i tom?







The answer coming soon.




or not.