OK
This problem can be simplified, if we consider the situation where we are jumping on the north pole. Also, we can consider the jumper and the earth as a whole system.
In this instance, we have 2 vector quantities: The system's rotational velocity (1 revolution per day) and the jumper's linear velocity (m/s upwards, as they jump).
The jumper remains part of the whole rotating system, even if he is in the air, because the jumper's rotational velocity has not been affected.
The above explanation assumes the jumper does not exert any torque (rotational force) during the jump.