This is perfectly in tune with gravitation through acceleration. See the Equivalence Principle.
I said in that very quote that the means by which the gravitational field comes into existance are irrelevant. The fact remains that the field strength is directly proportional to mass, and the field is omnidirectional.
Now, let me do something with this theory that you refuse to do - Apply concrete numbers.
Now, you do not claim that no variance in Gravitational acceleration is ever observed. You postulate that the difference with altitude is caused by the gravitational pull of the Sun and Moon. Now, ignoring for a moment that this model would cause the observed variance to itself be variable with A) Seasons and B) The time of day, (as both of these would varry the distances between the sun and moon, and thus the attractive forces they exert) We will determine what mass the sun requires to cancel 0.01 N / kg of force on an object at the peak of Mount Everest (8.85 km above sea level) and from there examine the variance in measured gravity which would result from this mass.
So, let us suppose it is noon on the day that the sun passes directly over the peak. It is at this time that the Sun would exert greatest force on an object there. (Never mind that Everest is North of the Tropic of cancer, so the sun would never come directly overhead)
The FE sun has an altitude of 3000 Miles, or 4827m. (Odly enough, this would mean that the peak of Mt Everest is actualy 4.0 km ABOVE the FE Sun...)
Let's slide
that litle contradiction under the carpet for a moment and go ahead with saying that the Sun is 4.8km away.
Supposing a unit-mass (m
1) on the peak of the mountain, experiencing 0.01N of force:
F = Gm
1m
2 / r
2(0.01) = (6.67E-11)(1)m
2 / 4800
2(0.01)(2.304E9) = (6.67E-11)m
2m
2 = (2.304E7)/(6.67E-11)
m
2 =
3.454E17 kgNow, given the dimentions of the Flat Earth, the altitude/position of the Sun's supposed path over it, and the mass which I have just found, you should be able to predict the variance in measured gravitational force at any altitude, position, time of day, and date on the Surface of Flat Earth by way of The law of gravitation, and Geometry.
[Note: if someone would like to pull up some numbers on the real-world observations of Gravity vs. Altitude, feel free to post them here and I will revise the mass of the FE Sun. The assumptions I used in genreating this number render the sun's mass lower than where it should be in order to fit said observations with a FE sun overhead at local noon.
Anyone whowould like to further explore the consequences of this mass of the sun being forced into a 30-mile sphere, go right ahead.