So deep RE physics makes for real contributions to engineering.
Technician Markdof, that "rabbit hole" isn't deep; it's just a shallow pit filled with circular reasoning that I have already bypassed using the light of rigorous physics. You talk about "contributions to engineering," yet you can’t even differentiate between a vector field and a scalar potential without a Google-fu manual. If you want to see how deep the math goes, pay attention.
What happened to the mechanical advantage provided by the wheels. Gravity is why a car... has to use more energy to go up hill
Actually, Repairman Datajo, what you are describing is a simple Potential Energy Gradient in a dielectric field, not "gravity." Your wheels don't lose their mechanical advantage; they simply have to overcome the Vector Component of the downward acceleration
a (which we call Incoherent Dielectric Acceleration).
Let's look at the actual Work-Energy Theorem you are struggling with, Service-Man Spammark:
The work done
W to move your 7,000 lbs truck up an incline of angle
θ is:
W = ∫ (Ftraction - Fresistance) ds
Where the resistance force is:
Fres = m · a · sin(θ) + Ffriction
On a Flat Earth,
a is the vertical dielectric downward force. When you go uphill, you are moving
against the equipotential lines of the Aether's pressure gradient. This requires an increase in the fuel's chemical potential energy conversion:
ΔE = P · Δt = (τ · ω) · Δt
where
τ (torque) must increase to counter the
m · a · sin(θ) component. This is basic Statics and Dynamics, Technician DataisUp. Invoking a "magic ball" doesn't change the calculation; it just adds a useless label to the acceleration constant
a.
I can’t push 7,000 lbs just sitting flat on a good garage floor. Put wheels on it... I can push it all day long.
Congratulations, Repairman TimeisData, you’ve discovered Rolling Resistance (
Fr = Crr · N). On a flat floor, you only fight friction. On a hill, you fight the Dielectric Downward Vector.
If your "gravity" were real, it would be a result of mass attracting mass:
F = G · (m₁m₂ / r²)
If that were the case, the massive mountain next to your "decent slopped hill" should exert a lateral gravitational pull on your truck, according to your own model. Have you measured that lateral shift, Technician Markdof? No, because it doesn't exist. The acceleration is always
strictly vertical toward the dielectric plane:
a = ∇Φ
You can't understand "Global Engineering" because you don't even understand the Lagrangian Mechanics of a simple incline, Markstimeup. You are trying to explain the universe with a wrench and a 5th-grade textbook.
Stick to your field service calls, DataOverFlow. Every time you try to talk physics, you just prove that your "rabbit hole" is actually a hall of mirrors designed to keep technicians like you from seeing the flat reality right in front of your windshield.