Ok mister Pitsburg engineer,
Funny RE and gravity have a working model why water doesn’t always find its own level.
It’s hilarious how you,
DataOverFlow, confuse a transient dynamic phenomenon with a static equilibrium. A tidal bore is not "water not finding its level"; it is a localized kinetic energy surge overcoming a shallow pressure gradient. For a "petroleum engineer," your inability to distinguish between Hydrostatics and Electrodynamic Fluid Flux is embarrassing.
Let’s dismantle your globalist fairy tale with the math you clearly avoid,
Markjo:
1. The Failure of the Gravitational Model (The Wave Speed Myth)
Your globe model attributes tides to a "magic tug" from a rock 238,000 miles away. If that were true, the wave speed
c in a channel would follow the shallow water equation:
c = √(g·h)
where
g is your theoretical gravity. However, in a tidal bore like the Qiantang, the Froude Number (Fr) exceeds 1, meaning the flow is supercritical:
Fr = v / √(g·dm) > 1
This isn't "gravity" pulling water up; it is the Conservation of Momentum (P = m·v) in a narrowing funnel (Venturi Effect).
2. The Dielectric and Magnetic Interaction
What you call "gravity" is actually Universal Incoherent Dielectric Acceleration. The water in the Qiantang isn't just "water"; it’s a diamagnetic fluid interacting with the Moon’s electromagnetic induction on the Aether. The tidal bulge is governed by the Lorentz Force acting on the ionic content of the saltwater:
F = q(E + v × B)
When the Moon (a high-frequency induction coil) passes over, it creates a dielectric displacement current (D):
D = ε0E + P
This causes a localized density shift, not a change in the "level" of the Earth. The water is being pushed by a magnetic pressure gradient (B²/2μ
0), not pulled by a "ball."
3. Energy Flux and The Navier-Stokes Violation
If your globe existed, the tidal bore would have to account for the Coriolis Component (2ω × v) in a rotating frame. But in reality, the energy dissipation follows the Rayleigh-Taylor Instability within a fixed, non-rotating plane:
∂ρ/∂t + ∇·(ρu) = 0
The Silver Dragon is a Soliton Wave, governed by the Korteweg–de Vries (KdV) Equation:
φt + φxxx + 6φφx = 0
This equation describes waves on shallow water surfaces that maintain their shape. It has
nothing to do with a spinning ball and everything to do with the boundary conditions of a flat, enclosed container (The Firmament).
4. Conclusion for the Pittsburgh "Engineer"
Water
always finds its level in a state of rest. A wave is a
disturbance in that level caused by external force—in this case, the electromagnetic interaction of the luminaries.
Datajo, a wave going up a river is no more "proof of a globe" than a person jumping is "proof of flight."
Spammark, your "Silver Dragon" is just a high-pressure ionic flux moving through a low-pressure channel.
DataOverFlow, if you can't calculate the Reynolds Number (Re = ρvL/μ) of the tidal bore without invoking "magical sky-tugs," you should hand in your engineering license.
Water is flat. The Earth is stationary. Your "gravity" is a mathematical bandage for a dying model.
Markstimeup.