Problem with UA

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

It is possible that this effect is what causes liquid magma below the surface, although I am just speculating. 

Why would the sun and moon, however, experience the same force?

It is possible that this effect is what causes liquid magma below the surface, although I am just speculating. 

Why would the sun and moon, however, experience the same force?

Actually it's that the acceleration of the Earth would be slowed down because not all of the Earth is affected by universal acceleration. However all of the Sun and the moon would be affected by universal acceleration.

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Imagine you were using a magnet to pick up two objects, one entirely made of iron, out one half wood half iron. The pure iron would accelerate faster towards the magnet. The pure iron object here is the Sun and the Moon, while the half wood half iron is the earth. After all, we know adleast the top few kilometers of the earth aren't affected by UA

Quote from: SeekerOfTruth on September 27, 2013, 10:34:35 AM

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Alright, have you ever gone scuba-diving? Or even swan to the bottom of a deep pool? You feel the pressure right? But isn't there water (and hence pressure from it) all around you? And yes of course the density of water and air are different, but we're taking just pressures here. So why do you feel it underwater and not on land?

Quote from: rottingroom on September 27, 2013, 10:36:50 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:34:35 AM

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Alright, have you ever gone scuba-diving? Or even swan to the bottom of a deep pool? You feel the pressure right? But isn't there water (and hence pressure from it) all around you? And yes of course the density of water and air are different, but we're taking just pressures here. So why do you feel it underwater and not on land?

I think that density is massively important. The water above your head is pushing down on you with an enormous force. In the atmosphere however the particles are so light and are in state of chaos and gravity isn't able to have it's way with it. Things like Biefield-Brown effect and air circulation are making that pressure significantly less. That's my pseudo-science answer.

Quote from: SeekerOfTruth on September 27, 2013, 10:58:13 AM

Quote from: rottingroom on September 27, 2013, 10:36:50 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:34:35 AM

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Alright, have you ever gone scuba-diving? Or even swan to the bottom of a deep pool? You feel the pressure right? But isn't there water (and hence pressure from it) all around you? And yes of course the density of water and air are different, but we're taking just pressures here. So why do you feel it underwater and not on land?

I think that density is massively important. The water above your head is pushing down on you with an enormous force. In the atmosphere however the particles are so light and are in state of chaos and gravity isn't able to have it's way with it. Things like Biefield-Brown effect and air circulation are making that pressure significantly less. That's my pseudo-science answer.

Hmmm, there are currents and circulations in water too. Answer my previous question assuming you go down into an empty water-well, where the currents can't get you. 

Quote from: rottingroom on September 27, 2013, 10:36:50 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:34:35 AM

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Alright, have you ever gone scuba-diving? Or even swan to the bottom of a deep pool? You feel the pressure right? But isn't there water (and hence pressure from it) all around you? And yes of course the density of water and air are different, but we're taking just pressures here. So why do you feel it underwater and not on land?

Yes I have. I feel the water pressure towards me from all over me, not just from above (otherwise it would be more difficult for me to resurface the deeper I dive).

Quote from: rottingroom on September 27, 2013, 11:02:00 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:58:13 AM

Quote from: rottingroom on September 27, 2013, 10:36:50 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:34:35 AM

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Alright, have you ever gone scuba-diving? Or even swan to the bottom of a deep pool? You feel the pressure right? But isn't there water (and hence pressure from it) all around you? And yes of course the density of water and air are different, but we're taking just pressures here. So why do you feel it underwater and not on land?

I think that density is massively important. The water above your head is pushing down on you with an enormous force. In the atmosphere however the particles are so light and are in state of chaos and gravity isn't able to have it's way with it. Things like Biefield-Brown effect and air circulation are making that pressure significantly less. That's my pseudo-science answer.

Hmmm, there are currents and circulations in water too. Answer my previous question assuming you go down into an empty water-well, where the currents can't get you.

Yes that water above your head is very dense. Water has a density of 1,000.00 kg/m³ where as the density of air is constantly fluctuating at a much smaller amount. Unlike the water in a cloud, water in a body of water in the ocean, lake or even a well is all connected as a blob of sorts. Each stack of water above your head puts ever more pressure on the stack below it until ultimately, your head.

Quote from: SeekerOfTruth on September 27, 2013, 10:58:13 AM

Quote from: rottingroom on September 27, 2013, 10:36:50 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:34:35 AM

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Alright, have you ever gone scuba-diving? Or even swan to the bottom of a deep pool? You feel the pressure right? But isn't there water (and hence pressure from it) all around you? And yes of course the density of water and air are different, but we're taking just pressures here. So why do you feel it underwater and not on land?

Yes I have. I feel the water pressure towards me from all over me, not just from above (otherwise it would be more difficult for me to resurface the deeper I dive).

Right!

Quote from: SeekerOfTruth on September 27, 2013, 11:24:55 AM

Quote from: rottingroom on September 27, 2013, 11:02:00 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:58:13 AM

Quote from: rottingroom on September 27, 2013, 10:36:50 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:34:35 AM

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Alright, have you ever gone scuba-diving? Or even swan to the bottom of a deep pool? You feel the pressure right? But isn't there water (and hence pressure from it) all around you? And yes of course the density of water and air are different, but we're taking just pressures here. So why do you feel it underwater and not on land?

I think that density is massively important. The water above your head is pushing down on you with an enormous force. In the atmosphere however the particles are so light and are in state of chaos and gravity isn't able to have it's way with it. Things like Biefield-Brown effect and air circulation are making that pressure significantly less. That's my pseudo-science answer.

Hmmm, there are currents and circulations in water too. Answer my previous question assuming you go down into an empty water-well, where the currents can't get you.

Yes that water above your head is very dense. Water has a density of 1,000.00 kg/m³ where as the density of air is constantly fluctuating at a much smaller amount. Unlike the water in a cloud, water in a body of water in the ocean, lake or even a well is all connected as a blob of sorts. Each stack of water above your head puts ever more pressure on the stack below it until ultimately, your head.

Yes but according to RE scientist, the pressure you feel from air DECREASES as you increase elevation. Hence it behaves the same as water. Even though the air fluctuates, it still produces pressure.

Quote from: rottingroom on September 27, 2013, 11:30:47 AM

Quote from: SeekerOfTruth on September 27, 2013, 11:24:55 AM

Quote from: rottingroom on September 27, 2013, 11:02:00 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:58:13 AM

Quote from: rottingroom on September 27, 2013, 10:36:50 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:34:35 AM

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Alright, have you ever gone scuba-diving? Or even swan to the bottom of a deep pool? You feel the pressure right? But isn't there water (and hence pressure from it) all around you? And yes of course the density of water and air are different, but we're taking just pressures here. So why do you feel it underwater and not on land?

I think that density is massively important. The water above your head is pushing down on you with an enormous force. In the atmosphere however the particles are so light and are in state of chaos and gravity isn't able to have it's way with it. Things like Biefield-Brown effect and air circulation are making that pressure significantly less. That's my pseudo-science answer.

Hmmm, there are currents and circulations in water too. Answer my previous question assuming you go down into an empty water-well, where the currents can't get you.

Yes that water above your head is very dense. Water has a density of 1,000.00 kg/m³ where as the density of air is constantly fluctuating at a much smaller amount. Unlike the water in a cloud, water in a body of water in the ocean, lake or even a well is all connected as a blob of sorts. Each stack of water above your head puts ever more pressure on the stack below it until ultimately, your head.

Yes but according to RE scientist, the pressure you feel from air DECREASES as you increase elevation. Hence it behaves the same as water. Even though the air fluctuates, it still produces pressure.

And it does, but that air doesn't stack above you in the way water does. With water the entire stack is pushing down on you while with air this doesn't seem to be the case. Each air parcel is on it's own. Some of them moving synchronously with others but still, each parcel of air is not bounded to another.

Quote from: SeekerOfTruth on September 27, 2013, 11:39:36 AM

Quote from: rottingroom on September 27, 2013, 11:30:47 AM

Quote from: SeekerOfTruth on September 27, 2013, 11:24:55 AM

Quote from: rottingroom on September 27, 2013, 11:02:00 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:58:13 AM

Quote from: rottingroom on September 27, 2013, 10:36:50 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:34:35 AM

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Alright, have you ever gone scuba-diving? Or even swan to the bottom of a deep pool? You feel the pressure right? But isn't there water (and hence pressure from it) all around you? And yes of course the density of water and air are different, but we're taking just pressures here. So why do you feel it underwater and not on land?

I think that density is massively important. The water above your head is pushing down on you with an enormous force. In the atmosphere however the particles are so light and are in state of chaos and gravity isn't able to have it's way with it. Things like Biefield-Brown effect and air circulation are making that pressure significantly less. That's my pseudo-science answer.

Hmmm, there are currents and circulations in water too. Answer my previous question assuming you go down into an empty water-well, where the currents can't get you.

Yes that water above your head is very dense. Water has a density of 1,000.00 kg/m³ where as the density of air is constantly fluctuating at a much smaller amount. Unlike the water in a cloud, water in a body of water in the ocean, lake or even a well is all connected as a blob of sorts. Each stack of water above your head puts ever more pressure on the stack below it until ultimately, your head.

Yes but according to RE scientist, the pressure you feel from air DECREASES as you increase elevation. Hence it behaves the same as water. Even though the air fluctuates, it still produces pressure.

And it does, but that air doesn't stack above you in the way water does. With water the entire stack is pushing down on you while with air this doesn't seem to be the case. Each air parcel is on it's own. Some of them moving synchronously with others but still, each parcel of air is not bounded to another.

The whole point is that despite local fluctuations in density due to currents, on a large scale air still contrives to create a measurable pressure. This is not really an issue of debate, both RE and FE agree on this. They disagree on what CAUSES the pressure, not whether it is there. FE say it is caused by UA, RE say it is caused by gravity. That is the issue here.

Quote from: rottingroom on September 27, 2013, 11:45:49 AM

Quote from: SeekerOfTruth on September 27, 2013, 11:39:36 AM

Quote from: rottingroom on September 27, 2013, 11:30:47 AM

Quote from: SeekerOfTruth on September 27, 2013, 11:24:55 AM

Quote from: rottingroom on September 27, 2013, 11:02:00 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:58:13 AM

Quote from: rottingroom on September 27, 2013, 10:36:50 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:34:35 AM

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Alright, have you ever gone scuba-diving? Or even swan to the bottom of a deep pool? You feel the pressure right? But isn't there water (and hence pressure from it) all around you? And yes of course the density of water and air are different, but we're taking just pressures here. So why do you feel it underwater and not on land?

I think that density is massively important. The water above your head is pushing down on you with an enormous force. In the atmosphere however the particles are so light and are in state of chaos and gravity isn't able to have it's way with it. Things like Biefield-Brown effect and air circulation are making that pressure significantly less. That's my pseudo-science answer.

Hmmm, there are currents and circulations in water too. Answer my previous question assuming you go down into an empty water-well, where the currents can't get you.

Yes that water above your head is very dense. Water has a density of 1,000.00 kg/m³ where as the density of air is constantly fluctuating at a much smaller amount. Unlike the water in a cloud, water in a body of water in the ocean, lake or even a well is all connected as a blob of sorts. Each stack of water above your head puts ever more pressure on the stack below it until ultimately, your head.

Yes but according to RE scientist, the pressure you feel from air DECREASES as you increase elevation. Hence it behaves the same as water. Even though the air fluctuates, it still produces pressure.

And it does, but that air doesn't stack above you in the way water does. With water the entire stack is pushing down on you while with air this doesn't seem to be the case. Each air parcel is on it's own. Some of them moving synchronously with others but still, each parcel of air is not bounded to another.

The whole point is that despite local fluctuations in density due to currents, on a large scale air still contrives to create a measurable pressure. This is not really an issue of debate, both RE and FE agree on this. They disagree on what CAUSES the pressure, not whether it is there. FE say it is caused by UA, RE say it is caused by gravity. That is the issue here.

Agreed, but you asked me why pressure is so much more apparent in water than air and I gave you what I see to be a reasonable answer.

Quote from: SeekerOfTruth on September 27, 2013, 11:53:50 AM

Quote from: rottingroom on September 27, 2013, 11:45:49 AM

Quote from: SeekerOfTruth on September 27, 2013, 11:39:36 AM

Quote from: rottingroom on September 27, 2013, 11:30:47 AM

Quote from: SeekerOfTruth on September 27, 2013, 11:24:55 AM

Quote from: rottingroom on September 27, 2013, 11:02:00 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:58:13 AM

Quote from: rottingroom on September 27, 2013, 10:36:50 AM

Quote from: SeekerOfTruth on September 27, 2013, 10:34:35 AM

Quote from: 11cookeaw1 on September 27, 2013, 10:08:28 AM

Quote from: SeekerOfTruth on September 27, 2013, 08:57:03 AM

Quote from: 11cookeaw1 on September 25, 2013, 09:15:09 PM

One problem with UA is that the ground is not affected by it. So the rock deeper in the earth must have a force exerted on them by UA equivalent to more then 9.81N/Kg The sun and the moon would likely experience the same force, so would accelerate faster.

I do not understand this statement. UA gives the acceleration, which is the force per unit mass. Of course EVERYTHING that has a different mass would feel a corresponding different force in order to keep the ratio constant. This is why things have different WEIGHTS when you put them on a scale. UA is consistent here. If you weigh more than me (I'm not calling you fat, its just an example  ), you FEEL heavier, you feel a different (larger) force due to the acceleration. This holds for all objects, from rocks in the ground to the Sun. This is in fact how we DEFINE mass.

The thing is that only part of the Earth would be affected by universal acceleration, since if you pick up a rock it falls to the ground. But all of the Sun and the moon are affected.

Well yes, but there is atmosphere above the rock,  which is not above the Sun and Moon. You would not expect a similar behaviour. But this raises a question: if it is the air that pushes the rock back down to the ground, why do we not feel the pressure form the air when we go outside, like a "gushing" of air on our heads? Well in fact we do but are used to it, the atmosphere HAS a pressure, it is something like 1.05*10^5 pascals at sea(-ish) level. Precisely what you would get from a AU of 9.8 m.s^2.

As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around.

Alright, have you ever gone scuba-diving? Or even swan to the bottom of a deep pool? You feel the pressure right? But isn't there water (and hence pressure from it) all around you? And yes of course the density of water and air are different, but we're taking just pressures here. So why do you feel it underwater and not on land?

I think that density is massively important. The water above your head is pushing down on you with an enormous force. In the atmosphere however the particles are so light and are in state of chaos and gravity isn't able to have it's way with it. Things like Biefield-Brown effect and air circulation are making that pressure significantly less. That's my pseudo-science answer.

Hmmm, there are currents and circulations in water too. Answer my previous question assuming you go down into an empty water-well, where the currents can't get you.

Yes that water above your head is very dense. Water has a density of 1,000.00 kg/m³ where as the density of air is constantly fluctuating at a much smaller amount. Unlike the water in a cloud, water in a body of water in the ocean, lake or even a well is all connected as a blob of sorts. Each stack of water above your head puts ever more pressure on the stack below it until ultimately, your head.

Yes but according to RE scientist, the pressure you feel from air DECREASES as you increase elevation. Hence it behaves the same as water. Even though the air fluctuates, it still produces pressure.

And it does, but that air doesn't stack above you in the way water does. With water the entire stack is pushing down on you while with air this doesn't seem to be the case. Each air parcel is on it's own. Some of them moving synchronously with others but still, each parcel of air is not bounded to another.

The whole point is that despite local fluctuations in density due to currents, on a large scale air still contrives to create a measurable pressure. This is not really an issue of debate, both RE and FE agree on this. They disagree on what CAUSES the pressure, not whether it is there. FE say it is caused by UA, RE say it is caused by gravity. That is the issue here.

Agreed, but you asked me why pressure is so much more apparent in water than air and I gave you what I see to be a reasonable answer.

You said: "As far as I know we don't feel that pressure because that pressure is spread equally all around us. If it was only on one side then you would obviously be pushed around."

And my reply is to state that even if the pressure is all around us we still feel it, like when under water.