OK, jroa, how could all the capacitors in this circuit have the same current going through them?

Let us start from the bottom left and work our way to the top left. Capacitors will be labels C1 thru C4 starting at the bottom left and working around counter clockwise.

Let us assume that all junctions split the current equally for ease of seeing things.

-Current

**X** enters and splits off into L1, R, and C1. The current going through C1 is

**X/3**. It appears that this is the current flowing through all the capacitors according to your statement that all the capacitors are in series.

-Current

**X/3** then gets split at the next junction point. So between L2 and C2. Current flowing through C2 is

**X/6**.

-Current

**X/6** then joins up with current from the resistor, which was

**X/3**. So this current is now

**X/2**.

-Current is now split between going off to the right and through L3. Which is now

**X/4**.

Now to the upper right.

-Current

**X/4** from the right joins the current

**X/4** from L3. So we have

**X/2** back there which is flowing through C3.

-So

**X/2** through C3 now joins up with current

**X/6** from L2. We now have a current of

**2X/3** flowing through C4.

-This then joins up with the current

**X/3** from L1. This brings us back to a current of X.

So now we have the currents flowing through the capacitors.

C1 = X/3

C2 = X/6

C3 = X/2

C4 = 2X/3

So tell me, why would you claim that all the capacitors have the same current flowing through them?

Oh wait, thats right, you are ignoring all the other components in the circuit. Silly me, I guess we don't need inductors or a resistor in this circuit.