2221
Technology, Science & Alt Science / Re: Ghosts
« on: October 02, 2008, 06:57:46 AM »
So do you think ghosts exist now with my mathematical proof?
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2222
Flat Earth Debate / profits for guarding ice wall
« on: October 02, 2008, 06:55:20 AM »
we all know that rational human beings do not do things unless the marginal benefit is equal or greater than the marginal cost...
The cost for defending the ice wall would be enormous... You would have to buy aircraft, employ thousands of men and as far as we know there is no benefit.. Why would anyone want to guard the ice wall?
The cost for defending the ice wall would be enormous... You would have to buy aircraft, employ thousands of men and as far as we know there is no benefit.. Why would anyone want to guard the ice wall?
2223
Technology, Science & Alt Science / Re: Ghosts
« on: October 01, 2008, 10:37:32 PM »
I acknowledge that my mass and momentum calculations were wrong. I have since fixed all the errors and I still disagree with you.
I would like to see how you calculated you mass equivalent differently then me.
I would like to see how you calculated you mass equivalent differently then me.
2224
Flat Earth Debate / Re: moon a disk
« on: October 01, 2008, 07:03:11 PM »This thought just crossed my mind for the first time. OK so if everything is accelerating upwards, and lets just say we could put someone on the round moon, wouldn't everything just fall off of the moon unless it was on the very top? I am interested in hearing theories that would disprove this.
The FAQ says the Moon is a disc. Plus, space flight is impossible in FET. Oh and the FET dark energy would ensure that they accelerate upwards as well, since the Moon is unlikely to provide as much 'shielding' as the Earth does. Oh yeah, and the Moon in FET gravitates as well (I think).
2225
Technology, Science & Alt Science / Re: Ghosts
« on: October 01, 2008, 06:50:21 PM »
Well the wave in which the violet colored ghost is moving oscillates that many times a second.
The cameras are "slow" because the wave is occurring so fast the camera will only see a blur and not the actual wave. Since during the time a camera has to take a picture the wave will have oscillated thousands of times already.
With a UV camera I suspect you will see lots of ghost blurs if ghosts are around. The data I have produced is for ghosts that happen to be colored violet so ghosts with a wavelength of about 400 nanometers. So pretty close to ultraviolet wavelengths... I pulled my wavelength data from a nasa page that said Violet is 400 nm... although nasa cannot be trusted...
The cameras are "slow" because the wave is occurring so fast the camera will only see a blur and not the actual wave. Since during the time a camera has to take a picture the wave will have oscillated thousands of times already.
With a UV camera I suspect you will see lots of ghost blurs if ghosts are around. The data I have produced is for ghosts that happen to be colored violet so ghosts with a wavelength of about 400 nanometers. So pretty close to ultraviolet wavelengths... I pulled my wavelength data from a nasa page that said Violet is 400 nm... although nasa cannot be trusted...
2226
Flat Earth Debate / moon a disk
« on: October 01, 2008, 05:02:28 PM »
how can you account for the moons phase changes if it is a disk? my friends in the university dont believe me the earth may be flat because of this phenomena
2227
Technology, Science & Alt Science / Re: Ghosts
« on: October 01, 2008, 04:21:34 PM »
let me state it like this
I=F*t
to make a ghost have no momentum one would need a apply a force of x for one second
for
(make negative because force and momentum are vector)
-1.656e-275 = F*T
-1.656e-27/1 = F
F= 1.656e-27 N for one second
at such low momentum it is like you are walking through air
and ghosts are operating at such a high frequency they are beyond what our eyes can see:
E=h*f
4.9661965318821405e-19 = 6.6260689*10e34 * f
4.9661965318821405e-19 / 6.6260689*10e34 = f
f = 7.49493645e15
t= 1/f
t = 1/7.49493645e15
t= 1.33423412816262104531*10^-16 seconds
a camera would have to capture that quickly. Todays cameras do not come close.
I=F*t
to make a ghost have no momentum one would need a apply a force of x for one second
for
(make negative because force and momentum are vector)
-1.656e-275 = F*T
-1.656e-27/1 = F
F= 1.656e-27 N for one second
at such low momentum it is like you are walking through air
and ghosts are operating at such a high frequency they are beyond what our eyes can see:
E=h*f
4.9661965318821405e-19 = 6.6260689*10e34 * f
4.9661965318821405e-19 / 6.6260689*10e34 = f
f = 7.49493645e15
t= 1/f
t = 1/7.49493645e15
t= 1.33423412816262104531*10^-16 seconds
a camera would have to capture that quickly. Todays cameras do not come close.
2228
Technology, Science & Alt Science / Re: Ghosts
« on: October 01, 2008, 04:05:55 PM »
Thanks TychoBC for proving that ghosts have mass.
We can find out precisely how much mass violet ghosts have as well from the equation
E= hc/λ
Since H and C are constant we only need to divide hc by the wavelength of violet.
We get
(6.6260689*10^-34 * 2.99797458*10^8) / (400*10^-9) =
4.9661965318821405e-19 Joules
Since we know that E=mc^2 we can now figure out the mass
4.9661965318821405e-19 J = Mass * (2.99797458*10^8 m/s)^2
Mass = 4.9661965318821405e-19 / (2.99797458*10^8)^2
Mass of ghost with one photon = 5.5254e-36 kilograms
Now with mass and velocity (c) we are able to calculate the momentum of roaming ghosts with the assumption that ghosts are moving as electromagnetic waves...
p=m*v
p= 5.5254e-36 * 2.99797458*10^8 =
1.656e-27 N*S
This low momentum is probably why we don't notice very many ghosts.
We can find out precisely how much mass violet ghosts have as well from the equation
E= hc/λ
Since H and C are constant we only need to divide hc by the wavelength of violet.
We get
(6.6260689*10^-34 * 2.99797458*10^8) / (400*10^-9) =
4.9661965318821405e-19 Joules
Since we know that E=mc^2 we can now figure out the mass
4.9661965318821405e-19 J = Mass * (2.99797458*10^8 m/s)^2
Mass = 4.9661965318821405e-19 / (2.99797458*10^8)^2
Mass of ghost with one photon = 5.5254e-36 kilograms
Now with mass and velocity (c) we are able to calculate the momentum of roaming ghosts with the assumption that ghosts are moving as electromagnetic waves...
p=m*v
p= 5.5254e-36 * 2.99797458*10^8 =
1.656e-27 N*S
This low momentum is probably why we don't notice very many ghosts.
2229
Technology, Science & Alt Science / Re: Ghosts
« on: October 01, 2008, 10:03:43 AM »
if you look at the equation e=mc^2 it is clearly possible that there are ghosts moving around but cannot be seen. This is explained with planks constant.
2230
Flat Earth Debate / Expedition to the ice wall
« on: October 01, 2008, 08:55:20 AM »
Hi fellow compatriots, I am planning an expedition to the ice wall.
I plan to buy a flight to Argentina, where the fascist US government cannot control us. Then I will lead a group of followers on our ascent to the Ice wall. I am a former private investigator so I have experience sneaking around... I will use a short wave radio to broadcast my discoveries....
Who wants to join
Hasta la victory!!!!!!!
I plan to buy a flight to Argentina, where the fascist US government cannot control us. Then I will lead a group of followers on our ascent to the Ice wall. I am a former private investigator so I have experience sneaking around... I will use a short wave radio to broadcast my discoveries....
Who wants to join
Hasta la victory!!!!!!!