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1
Technology, Science & Alt Science / What is a woman?
« on: April 09, 2023, 06:12:15 AM »
Below is the answer to the above which is a very common question on the internet

Ans -  A person who is not a man - Right?

Reasons:

A man has XY chromosomes while a woman has XX. This means a man can be a woman due to the presence of X in XY but a woman can’t be a man due to the lack of Y in XX.

A man can be pregnant but a woman can’t make a man pregnant.

No onslaught but didn't God create Eve from the ribs of Adam but not vice versa

So shouldn't all transgenders be considered as Men if they have a Y chromosome?

FYI: I just have a very basic knowledge of biology.

2
Here is my solution to Aristotle's wheel paradox.

https://en.wikipedia.org/wiki/Aristotle%27s_wheel_paradox

IMPOV - Time is the reason in Aristotle's wheel paradox. The tangential period of contact time of the inner circle is more than the tangential contact time of the outer circle. Each point of the inner circle stays longer on the line than each of the outer circles. The duration of the contact of each point of the outer circle is shorter than the duration of each inner circle on the line.

Let theta be the angle that produces arc A1 and arc A2 on the inner and outer circles of the aforementioned paradox respectively. The length of A1=2A2. There is an infinite number of points on each arc but for simplicity, we assume the number of points on A1=2A2. Let L and L’ (L=L’) be the lines produced by the aforesaid two circles upon one rotation/ roll. There is an infinite number of points on L as well which is equal to the circumference of the outer circle. For simplicity

At Rest: One point of the inner circle touches one point of L ‘ and one point of the outer circle lies/touches one point of L.

When the wheel is rolling: Depending upon the speed of rolling, if one point of A1 takes t seconds to stay on one point of the L then one point of A2 takes t/2 seconds to stay on that point during rolling. Or if the Meeting time of one point of A1 with one point of L is t second then the meeting time of A2 with one point of L will be t/2 seconds. So if the total number of points on the inner circle is = P, then The total number of points on the outer circle will be = 2P= total number of points on L Each point of P and 2P must touch/meet its respective point of L in one complete rotation/roll. So if the total time taken by each point of 2P is t seconds to stay/touch with its respective point on L then total the time taken by each point of P will be 2t seconds to touch its respective point on L”=L

I hope I have explained things clearly enough to understand.


Is anyone who disagrees with the above if yes then reasons, please?

3
IMPOV:

Zero is misunderstood. It means zilch which can’t be a number. It means the start of something.

Similarly, a point has always a diameter or linear dimension no matter how small it is even in imagination. The same analogy is applied to a "Line" which is made of "points"

4
Flat Earth General / Is the Heliocentric Model correct?
« on: March 01, 2023, 12:30:46 AM »
Reasons #1:

Since the solar day is longer than the sidereal day by about 4 minutes therefore the earth faces more daytime than nighttime on its surface. This shows that the occurrences of noons are more than the occurrences of anti-noons on the equatorial circumference of the earth in one complete year.

[# of noons must be equal to  # of anti-noons on the equatorial circumference of the earth if calculated for one year]

No need to go into detail as we all know about the leap years or after six months midnight is noon and vice versa on the earth. This is just for the compensation of a true day of 24 hours to occur by allowing the “ solar noon” position to be facing the sun every day equally in Heliocentric Model.

Reasons #2:

The earth traces out a path (two concentric circles for simplicity) in its top view when it rotates about its own axis and orbits around the sun in one year.

Draw a third or mid-circle in b/t aforementioned two concentric circles.

The area in b/t outer circle and the mid circle represents the total nighttime on the earth in one complete year.

The area in b/t inner circle and the mid-circle represents the total daytime on the earth in one complete year.

Any point on the outer circle represents midnight while any point on the inner circle represents noon.

The circumference of the outer circle is greater than the inner circle therefore it shows the occurrences of midnight are more than the occurrences of noon.

For the diagram, there is a link in reply #2 in the following link.

https://www.theflatearthsociety.org/forum/index.php?topic=76422.0

Reason #1 not only contradicts Reason #2 (both are opposite statements) but also even if the # midnights = # of noons in Reason#2 for the sake of argument.

Similarly, were the Heliocentric Model true, the temperature of the earth would have risen too high catastrophically in Heliocentric Model that the earth wouldn’t even be suitable for living today due to global warming (more daytime than nighttime on earth).

5
Which one of the following is true for the existence of gravitational force (F=GMm/d^2) between two identical two concentric rings?

1-   F = GMm/d^2 = Infinity as the on-center distance “d” = 0
2-   F = GMm/d^2 = Zero as G = Fd/Mm = 0 as the on-center distance “d” = 0

6
Multiplication = Repetition of addition
Division = Repetition of subtraction

Examples

5 x 4 = 20
5 x 4 = Add 5 four times
4 x 5 = Add 4 five times
5 x 4 = 5 + 5 + 5 + 5 = 4 + 4 + 4 + 4 + 4 = 20
Therefore
5 x 4 = 5 + 5 + 5 + 5 = 4 + 4 + 4 + 4 + 4 = 20

Similarly

20 / 5 = 4/1 = (1/4) of 20 + (1/4) of 20 + (1/4) of 20 + (1/4) of 20 = 5 + 5 + 5 + 5 = 20

Check

20 – (1/5) of 20 - (1/5) of 20 - (1/5) of 20 - (1/5) of 20 - (1/5) of 20 = 20 - 4 - 4 - 4 - 4 - 4 = 20 – 20 = 0 = Nothing left as each of 5 persons gets 4

OR

20 / 4 = 5 = (1/5) of 20 + (1/5) of 20 + (1/5) of 20 + (1/5) of 20 + (1/5) of 20 = 4 + 4 + 4 + 4 + 4 = 20

Check

20 – (1/5) of 20 - (1/5) of 20 - (1/5) of 20 - (1/5) of 20  = 20 – 4 - 4 - 4 - 4 - 4 = 20 – 20 = 0 = Nothing left

Any number divided by one or x/1 is not equal to that number or x but equal to x per 1. Let x = 20 so

20 / 1 = 20 – 1 of 20 = 20 – 20 = 0 = Nothing left as one person takes the whole

Similarly, any number divided by zero or x/0 = x is not equal to infinity or undefined.

Let x = 20
20 / 0 = 20 – (0 = zero) of 20 = 20 – 0 = 20 = left 20 because there is no one to take it whole 20 or in parts

Check

20 - 0 = 20

Similarly, we get zero when we multiply any number with zero. For example

5 x 0 = Add 5 zero times (No addition happens) = 0
0 x 5 = Add 0 five times = 0 + 0 + 0 + 0 + 0 = 0

Clarification

For explanation purposes, divide 20 oranges among 5 persons.

We get 20 (oranges)/5 (persons) = not just 4 but 4/1 where 1 stands for a person while 4 stands for oranges.

In order to avoid confusion, we must write the answer in its simple form of 4 oranges per person or 4/1. This implies all divisions. 

Conclusion

Any number divided by zero is not equal to infinity or undefined but remains the same

20 / 0 = 20 / 0, not equal to 20 - we get 0 = 0 after cross multiplication
20 / 1= 20 / 1, not equal to 20 - we get 20 = 20 or 1 = 1 after cross multiplication

Since no actual division happens in all of the following therefore

x / 0 = y / 0 = z / 0, we get the following by cross multiplication - Where x , and z are different number numbers

x .0 = y. 0 = 0.z

0 = 0 = 0

Regarding one divide by a large number say divide one orange among 10^100000 people.

No matter how big the number of people, each will get something but not equal to zero after repeating the aforementioned process of repetition of subtraction that we did for 20/5 at the start.

Regarding small number

We can’t just write 1/10^(-100000000000) = 1/0 as 1/10^(-100000000000) represent a huge number if the above procedure of repetitions is followed and vice versa

The graph will never touch the x or y axis as long as there is a division. No division (divided by zero) means the number will remain the same.

We must follow the rule in order to avoid confusion.

Your comments, please.



7
The Lounge / Free insertion of diagram or picture
« on: July 24, 2022, 04:33:32 AM »
I used the website of Postimages when I needed to post images for my questions or answers on this forum. Now Postimage is no longer free therefore is there any other way or website that can help for posting free images here in this forum.

8
Technology, Science & Alt Science / Zeno's paradox
« on: January 02, 2022, 12:49:38 AM »
Dichotomy paradox:
That which is in locomotion must arrive at the half-way stage before it arrives at the goal. Suppose Atalanta wishes to walk to the end of a path. Before she can get there, she must get halfway there. Before she can get halfway there, she must get a quarter of the way there. Before traveling a quarter, she must travel one-eighth; before an eighth, one-sixteenth; and so on.-  It is also said that travel over any finite distance can be neither completed nor begun, and so all motion must be an illusion

https://en.wikipedia.org/wiki/Zeno%27s_paradoxes#Dichotomy_paradox

Source - Wikipedia.

IMPOV

Any division in between 0 and 1 unit can be selected, not just half (0.5) as selected by Zeno.

Division by definition is an uncountable noun. A unit length can be divided into an infinite number of pieces, more precisely points.

There are two approaches – realistic and unrealistic/possible and impossible

Possible is practicable while impossible is impracticable. 

It is impossible to touch each and every point of the unit length - sliding on every point is possible

Not every series/ sequence/pattern of points is feasible as well - Therefore

A trekker must select a workable pattern of points that have to be touched on the course in order to reach the desired destination.


The pattern selected by Sir Zeno is non-achievable.   

Correct?

Addendum

Mathematically,

Let D be the total unit length that has to be covered and at any moment, d is the distance covered as required by the sequence of Zeno.

 d = 1/2 +1/4 + 1/8 ….

Add 1 to both LHS and RHS, at any moment t

1+ d = 1+ 1/2 +1/4 + 1/8 ….
1+ d = 1+ d
D=1=1=D ----------- RIGHT?

9
Flat Earth General / Time Dilation / Second Postulate
« on: December 07, 2021, 03:46:53 AM »
Let M1 and M2 be two mirrors attached to the ceiling and floor of a spaceship respectively deep in the space. O1 is stationed inside the spaceship while O2 is at rest on an asteroid as shown in a tentative diagram.

Distance “d” = Ct for all stationary observers.

We get a time dilation triangle ABC as shown when a spaceship moves with velocity “V” relative to O2. The equation of timed dilation may be derived from the right-angled triangle of ABC as shown.

Relative to O2: 

Vt is the distance covered by the M1 or M2 in un-dilated time t in space.

Ct is the distance covered by a pulse in un-dilated time t in space

Base = Vt and Hypotenous = Ct, where t is un-dilated time

Relative O1

Perpendicular BC = Ct’ is the distance covered by a pulse in dilated time t’


Since the speed of light is the same for all observers irrespective of their motion, therefore, both space and time are not absolute in order to make “C” constant for all observers.

CRUX #1

Although O1 feels himself at rest yet space in the direction in which he moves is contracted relative to other axes. This means,


1-    Dimension of the “time and space” change in the direction in which O1 moves say x-axis ONLY. However

2-    Dimension of the “time and space” don’t change in the direction of the y-axis and z-axis.

So in order to make the speed of light constant for O1.

1-    Dilated time has to be used in the direction in which O1 moves (x-axis) as space is contracted for O1

2-    Un-dilated time in the rest of the axes (y-axis and z-axis) as space doesn’t contract for O1 in the foregoing axes.

Since a pulse moves back and forth in a y-axis, therefore, the perpendicular of the right-angled triangle used for the derivation of the equation of time dilation will be = Ct, not Ct’ where t is un-dilated time while t’ is dilated time.

CRUX #2:

Although, O2 is unable to see the contraction of space for O2 yet O2 still sees O1 at a point B despite knowing that the dimension of time and space are changed for O1. This is so sad because the actual position of O2 would be somewhere in between A and B say @ P due to Vt’ (the ACTUAL distance covered by M1 or M2 in dilated time t’).

M1, M2, and O2 would disappear for O2 with the passage of time as they are lagging behind for O2 in both un-contracted space un-dilated time “t”.


10
Imagine there is an object “A”, which rests on the surface of the earth in the absence of all other gravities. “A” falls on earth due to F = GMm/d^2 and therefore it has “g=9.8 m/s/s = GM/d^2”. Let the earth is suddenly disappeared beneath the “A”.

Would “A” remain at rest at its original position in space or moves at its final velocity of 9.8 m/s in the direction in which it was attracted before the disappearance of the earth?
 
My answer is it would stay at its original position instead of moving at its final velocity of 9.8 m/s because “A” was at rest and therefore has to go through acceleration before attaining a velocity of 9.8 m/s and acceleration needs a force of whatever kind for its generation.

Weight of “A” on “Earth” = Mage where Ma is mass of “A” and ge is the acceleration due to the gravity of earth. This is balanced by normal force “N” opposite to Mage

Weight of “Earth” on “A”= Mega where Me is mass of Earth and ga is the acceleration due to the gravity of “A”. This is balanced by normal force “N” opposite to Mega.

In a nutshell, there is no net force as N = Mage = Mega = N. No force means, there exits no gravitational force at all times. So

Is "g = 9.8 m/s/s = GM/d^2 bona fide on the surface of earth?

11
All Muslims should face Qibla, which is the fixed direction towards the Ka'bah in the Grand Mosque in Makkah, Saudi Arabia when performing their prayers, wherever they are in the world.

This direction is changed for the Muslims who perform their prayers on the lower hemisphere (if Ka'bah is at the apex) of the globe roughly if a theoretical vertical line is extended vertically infinitely towards the sky right from the center of Ka'bah.

The same change occurs when the body of a Muslim is buried at a right angle to the Qibla and the face turned right towards Ka'bah. 

This means all Muslims should believe in flat earth unless the above is wrong.

Reference – Bilal Sajid (Youtuber - Jun 12, 2020)

12
Waves formed on the surface of the water upon disturbing due to gravity here on earth.

I don’t understand

What causes the light /photon to travel in the waveform or what causes the oscillation of the photon in its traveling?   

Why does a photon show its presence when it is massless either in wave or particle form?

13
Flat Earth General / Time dilation in horizontal light clock?
« on: November 22, 2020, 02:51:03 AM »
No time dilation is observed in a horizontal light clock if the horizontal velocity of a pulse is considered, which was ignored in the calculation? It ticks at the same rate no matter how fast it moves.

When a pulse moves toward the rear mirror:

Although a pulse moves towards the rear mirror with “c” but it has horizontal velocity ”v” in opposite direction to “c” as well, as the moving spaceship does in which the clock consists relative to the stationary observer. Considering alone c-v means both the pulse and front/space moves in two opposite directions with “c” and "v” respectively independently. Here in this case a pulse has "c" only. It doesn't have horizontal velocity "v" (opposite to "c") as a moving clock does.

A pulse has two velocities

1- "c" towards the rear mirror and

2- "v" with which it moves forward.

The net velocity of a pulse = c-v. This is relative to a stationary observer

Physics laws are the same in all inertial frames of reference therefore a pulse must have a horizontal velocity "v" at which the horizontal clock moves when a pulse bounces toward the rear mirror.

Both a pulse and the rear mirror move with the same horizontal velocity therefore the forward velocity "v" of the rear mirror never helps a pulse to strike with it earlier as taught. So it means the striking time of a pulse (with rear mirror) increases when the horizontal velocity of the moving spaceship increases.

Time dilation may be observed in the vertical light clock used by Einstein because the horizontal velocity of a light clock added to “c” never compensated.

Addendum: If C+V is possible then aforementioned explanation is also possible.


14
Technology, Science & Alt Science / Light clock doesn't work if moving?
« on: November 19, 2020, 10:02:00 AM »
A light clock shown in the following figure consists of four mirrors A, B, C, and D. Distances AB=BC=CD=DA. Angle ABC = Angle BCD= Angle CDA = Angle DAB =90o or θ1 = θ 2 = 45o degrees. The observer in the clock at point A is Oc. There is another stationary observer Os on an asteroid. A pulse of a light clock takes 1 second to complete a path of ABCDA or ADCBA for all stationary observers. The clock of Os is synchronized with the light clock before its journey into space. Let the said clock starts moving at a very high speed in space relative to Os.

It is observed that a pulse misses its upper target if the aforementioned light clock moves at any speed. It means a pulse of light doesn’t even hit mirror B if fired at A in its desired direction towards mirror B due to the speed of the light clock in its forward direction.

Even if the firing angle of a pulse is adjusted with the speed of a moving clock, then it (a pulse) still misses the lower target/ mirror “C” in its round trip if the speed of the light clock is less than the fifty percent speed of light.

A light clock can be designed in an infinite number of ways. So, is the light clock used by Einstein, which consists of two mirrors for the derivation of his famous equation of “Time Dilation” standard?

15
Please recheck the following before making your own calculation

Number of moles = Mass Given/(Atomic Mass) or Molecular Mass

Number of moles = Volume Given at STP/ 22.4 L (22.4 dm^3)

Number of moles = Molecule Given or Atoms Given/ Avogadro’s number 

WATER: One liter is defined as the volume of one kilogram of pure water at maximum density (+4 °C) and standard pressure

Number of moles = Volume Given at STP/ 22.4 L
Number of moles = 1 L/ 22.4 L
Number of moles = 0.04464286


Atomic mass of H2O = 16 + 2 = 18g/moles

Number of moles = Mass Given/(Atomic Mass) or Molecular Mass
Number of moles = 1000g/18
Number of moles = 55.556

PLATINUM: Of which the standard Kilogram is made of (https://en.wikipedia.org/wiki/Kilogram)
Atomic mass of platinum = 195.084
Mass of 1 Kg of Plaitinum = 1000 g

Number of moles = Mass Given/(Atomic Mass) or Molecular Mass
Number of moles = 1000/195.084
Number of moles = 5.125


One liter of platinum weighs 21.45 kg (source internet)

Therefore volume of one liter (1L) of platinum = 1/21.45 L=0.04662005

Number of moles = (1/21.45) L/ 22.4 L
Number of moles = 0.00208125

ANY REASONS
[/b]

16
Flat Earth General / Basic mathematical operation?
« on: September 08, 2020, 04:02:09 AM »
Can items of two or more different categories be multiplied or divide with one another except where ratio or per head is involved?

Items of different categories: TV, roads, fridge, bridges, car, trees, parrot, goats, jet, etc

Examples:

2 TV x 3 Trees x 6 fridges  = 12 (TV.Tree.Fridge)

6 Cars x 5 parrots x 7 goats x (5 bridges)^5clocks

(6 Tub lights + 7 doors)^10 moons

if the answer is no, then

How do we multiply mass and velocity in the mathematical formula of the momentum of "mv"?

Masses M and m, gravitational constant G and distance d in the mathematical formula of F= "GMm/d^2"

E="mc^2", mass with velocity

Etcetera

Can physics describe nature when it doesn't follow the basic mathematical operation?

17
Mass curve space around it if placed in space anywhere in the universe. Atomic particles, which all matters composed of, might have bent space-time slightly. Nuclei are about 100,000 times smaller than the atoms they’re housed in.  Atoms are the building blocks of matter therefore if 99.999% of our body is empty then aren’t all these celestial bodies as well. My questions are

Space-time is bent externally if we consider the whole mass of earth as a single closed mass

Space-time is bent within the earth if we consider the atomic particles of the whole mass of earth individually.

Shouldn’t the bending in space-time be equivalent in both cases?

Why would both time and space be bent externally at a distance, not even touched by a mass when they both (space and time) also exist within the mass of the subject? -

Mass can't occupy time but occupies space in time "t" therefore how are these incompatible two things connected as space-time?

Gravity is the property due to which things falls on mass, not mass therefore how it bends light

Similarly, if an atomic particle can bend space-time then would it change the shape of atom/compound too?

18
It is the gravitational ability of any point mass to accelerate all other point masses at [g=GM/(R+H)^2] towards its center either in free fall or on its surface, therefore what is role of gravitational force (F=GMm/d^2) b/t two point masses then when each object has an innate power to accelerate other object towards its center w/o any force F.

When there is a force there is a mass but the gravitational acceleration (g=GM/(R+H)^2) of each object is independent of falling mass though we can’t ignore the center of gravity of the falling mass and after all it is the mass which is falling or accelerated.

If the said object is earth then = g = 9.8 m/s/s, R=radius of earth, H = height above the surface of the earth, M=mass of the earth and G=gravitationlal constant

19
Flat Earth General / Flat Earthers - Is she correct.
« on: August 13, 2020, 12:34:44 PM »
Is she correct what she says about the equivalence principle and flat earth?

20
According to The Quran. The earth is stationary while the sun moves forward in space. Most celebrity Islamic scholars stretch Quran verses towards the solar system despite knowing the following unless I interpreted them wrongly.

https://quran.com/36/38-48?translations=20
https://quran.com/39/5
https://quran.com/55/5
https://quran.com/91

Similarly - “The angel Gabriel tells Muhammad (pbuh) that the sun moves forward 500 years* (The distance covered by a horse in their point of view) from the time Muhammad (pbuh) says “No” until the time he says “Yes” one after another”.
*(Another source says  Farsakhs ,1 Farsakh = c. 6 km)

Further -  There are seven earths and seven skies as per The Quran,.
https://quran.com/65/12
https://quran.com/41/12-22?translations=20

Furthermore -  "The Islamic picture of the universe in a nutshell - I'm not sure if muslim scholars certify it or not but "Ibn al-Wardī (d. 861/1457) sums up that the earth is upon water; the water—upon the rock; the rock—on the back of the bull; the bull—on a sandhill; the sandhill—on the whale/fish; the fish—upon a futile wind; the wind—on a veil of darkness and the darkness—on the humid ground. As to what is beneath the darkness, the knowledge of human kind fails. “Nobody knows it but God, who is the creator of heavens and earths" – Extracted from the PhD THESIS Submitted by KRISTINE CHALYAN-DAFFNER.

In addition - According Sahi Muslim (The book of Faith)# 0297
https://www.searchtruth.com/book_display.php?book=1&translator=2&start=290 - -
Pls read 0297
"It is narrated on the authority of Abu Dharr that the Messenger of Allah (may peace be upon him) one day said: Do you know where the sun goes? They replied: Allah and His Apostle know best. He (the Holy Prophet) observed: Verily it (the sun) glides till it reaches its resting place under the Throne. Then it falls prostrate and remains there until it is asked: Rise up and go to the place whence you came, and it goes back and continues emerging out from its rising place and then glides till it reaches its place of rest under the Throne and falls prostrate and remains in that state until it is asked: Rise up and return to the place whence you came, and it returns and emerges out from it rising place and the it glides (in such a normal way) that the people do not discern anything ( unusual in it) till it reaches its resting place under the Throne. Then it would be said to it: Rise up and emerge out from the place of your setting, and it will rise from the place of its setting. The Messenger of Allah (may peace be upon him) said. Do you know when it would happen? It would happen at the time when faith will not benefit one who has not previously believed or has derived no good from the faith".

21
No need to go in detail about the method of exhaustion in which area under the curve is estimated with rectangles.  It is said that a precise result can be obtained if we place the infinite number of thin rectangles under the curve above the x-axis. This means the width dx of each rectangle is infinitesimally small while the height of each rectangle varies (few may repeat depends on curve) says h1, h2, h3, ...........……hn.

Area of an infinitesimally small rectangle of height h1 and width dx = h1dx where dx tends to zero. The resulting area is very close to zero (almost zero or negligible) due to the very small value of h1. The areas of these infinite number of infinitesimally small rectangles are then added /integrated together for estimating the total area under the curve. Summation of infinite number of zeros is zero. Thus 

Area under curve = [h1dx +h2dx +h3dx …….hndx] = very close to zero or zero

Similarly, dx is common. Therefore = dx(h1+h2+h3………..…..hn) =dx(infinity) As dx tends to zero therefore infinity also became tends to zero and hence =0

Another option is undefined as infinity divided by infinity.

I’m not sure how other people think but IMPOV the integration of the Riemann method may not be the right way to determine the area under curve unless I’m conceiving it wrong – Correct if not how?

22
Technology, Science & Alt Science / Volume of a Sphere
« on: July 10, 2020, 10:47:56 AM »
We know the volume of a sphere is V=4πr3/3. How about the following.


23
Technology, Science & Alt Science / Mainstream Science
« on: July 05, 2020, 04:36:10 AM »
Does mainstream science (such as biology, physics, chemistry, astronomy, engineering, medical, social sciences, economics, etc) especially of the modern days and its application exact?

24
Why is the speed of light constant in all frames of reference when the speed of light is much greater than the escape velocity of any celestial body except the black hole?
Any special reason.

25
What is the swing of the Foucault pendulum, has to do with the rotation of the earth?

Foucault demonstrated the earth’s rotation via his famous pendulum. He suspended a 28-kilogram (62 lb) brass-coated lead bob with a 67-meter long (220 ft) wire from the dome of the Pantheon, Paris – Wikipedia

Here is the animation of Foucault's Pendulum.

https://upload.wikimedia.org/wikipedia/commons/8/82/Foucault-rotz.gif

Let mark a point “A” on the outer diameter (big enough) of the wire of Foucault's Pendulum, facing exactly west or any other specified direction. 

The wire of Foucault's Pendulum doesn’t spin during swinging in the experiment. It can be observed easily in the above animation – Right. It is the earth, which spins, not the wire of the pendulum. After 24 hours or more

Point “A” is also seen by the north, east, and south of the earth if the green trace in the above animation shows the path of the pendulum bob over the ground (a rotating reference frame).

I may be wrong but I suspect the force that sat the swing of the Foucault pendulum might not be in the perfect direction. The density of bob also affects the direction of the applied force.

Because

If the aforementioned experiment really shows the evidence of rotation of earth then we can also get the same result from the following experiment as well.

– Simply, here we don’t need the swing of the pendulum.
 
Let both the wire and the bob of the aforementioned experiment are at rest and don't rotate. Attached a laser light torch to the bob of the aforesaid pendulum such that it shines a laser light exactly toward the west (in a straight line) perpendicular to the above said 67-meter wire. OR it can be any mark on the wire or bob facing in a specified direction.

Remember: The wire used in the experiment of Foucault's Pendulum doesn't spin during swinging. 

After 24 hours or more

The laser light, in this case, is not seen by the north, east, and south of the earth - I believe.

What do you think?

Your comments, please!!!


26
Philosophy, Religion & Society / Social distance and corona virus
« on: June 07, 2020, 11:15:22 AM »
A healthy person with strong immune system emits germ as well as radiation (probably new term if unbeknownst to me) around its influence circle that may be good for another living being, therefore, does the direct or indirect contact (but close enough) of the said healthy person with a sick person who is affected by harmful germs or virus not just corona (not deadly) beneficial though it's hard to differentiate which side is of extremely negative and positive. Just a question. Absolutely I don’t encourage to avoid social distance

27
The gravity of the earth decreases when the height of the falling object increases and vice versa. The gravity of earth is 10 times less at the height of International Space Station (ISS) than on the surface of the earth.

The gravity of earth at the height of International Space Station (ISS) is about 90% of what it is on its surface (9.8 m/s/s)

The weight forces of ISS and the earth fail to attract each other closer because the horizontal velocity "v1" of the ISS is so high than its (or any falling object or sample of water in ISS) falling velocity "v" that every time ISS falls on a single gravity line on which it supposes to fall with vertical velocity, it misses that particular line and hop over to the next gravity line which consequently makes the path of falling object a circular orbit in space. In simple words, it just simply rides on the equipotential gravity lines due to the very high speed of ISS. This means the horizontal velocity of an object not only change the falling path of an object but also the striking time. Any falling object (not weightless) within ISS can be observed. Thus the greater the horizontal velocity of an object, the greater the change in its falling path (curve), and the greater the striking time as well.

Conclusion

This means the horizontal speed of the ship also makes the falling/striking time of an object greater than at rest on the ground (unnoticeable) if drops from the top of the mast. 

Let Og is an observer on the ground at rest and Os on ship.

A ball hits the ground at the same time “t1” for both Og and Os if drops from the top of the tower built on ground when the ship is at rest.

A ball hits the deck at the same time “t1” for both Og and Os if drops from the top of the mast when the ship is at rest.

A ball hits the ground at the same time “t1” for both Og and Os if drops from the top of the tower built on ground when the ship is moving.

A ball also hits the deck at the same time for both Og and Os but at “t2”, not “t1” if drops from the top of the mast of a moving ship.

Where t1 is always < t2 unless the ship is at rest.

The greater the speed of the ship the greater the curvature (simple curve to orbit) of the path of the any falling object in space.

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Technology, Science & Alt Science / Equivalence Principle
« on: October 05, 2019, 08:44:24 PM »
A light clock installed in the elevator of Einstein which is moving upward @ the rate of 9.8 m/s/s therein free space away from the local attraction of gravity consists of two mirrors, M1 (attached to the east wall) and M2 (attached to the west wall) facing each other at a distance "d" apart.

The beam will follow a straight horizontal path relative to the observer inside the accelerating elevator as he feels a ground condition.

Ok, there is another observer at rest outside the above elevator therein free space shines a flashlight horizontally from west across the elevator toward its far east wall (from west to east) but below or above the light clock.

The beam will follow a curved path downward relative to the observer inside the accelerating elevator.

So which one is right – please

Previous original post:
Following diagram shows the elevator used in the thought experiment by the Einstien for equivalence principle



Elevator at rest on earth: Light beams or pulses emit at A and D at the same time, respectively. Both beams/pulses reach their destination B and C at the same time.

Elevator accelerating @ 9.8 m/s/s in free space: Light beams or pulses emit at A and D at the same time, respectively. Both don't reach their destination B and C at the same time. Pulse on right of observer reaches C faster as the floor of the elevator approaches it than pulse on the left where pulse moves away from the floor of the elevator when the floor tries to approach it (difficult to catch) - Right

So should the distance covered by pulses/ beams in time "t" be the same in both aforementioned cases for equivalency reasons?

Same scenario but with light clock

A light clock installed in the elevator of Einstein consists of two mirrors, M1 (attached to the ceiling) and M2 (attached to the floor) facing each other at a reasonable height "h" apart. Would the bouncing pattern of light beam/ pulse in between M1 and M2 be the same (equivalent) when the elevator is at rest on the ground and moving upward @ the rate of 9.8 m/s/s therein free space away from the local attraction of gravity?

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Einstein theorized his gravity model on the basis that all objects, regardless of size or shape or weight, free fall at the same rate. If this is true then

Question #1: Why and how do objects sink in water (liquid) if its density is greater than that of water? – both water and sinking objects have same “g”

Question #1: Why does gravity become specific gravity in such cases?

Question #1: Why does specific weight (force) = density x acceleration due to gravity in the presence of equation of weight (force) w = mg, where g is constant for all masses irrespective size and shape near the surface of earth.

Watch this - - it may help

Sinking objects shouldn't penetrate if placed above the water bodies if all objects fall at the same rate on ground (near its surface) in the absence earth's atmosphere because both objects have the same "g". 

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Technology, Science & Alt Science / Question about fourth dimension?
« on: September 19, 2019, 08:07:08 PM »
It is said that dimension lines are not straight but slightly curve which finally ended up in bigger circles, as they are finite not infinite though seem close to infinite.

This means “time” which is considered the fourth dimension creates a bigger circle as well – right. So does this mean; everything is fixed and repetitive in nature? 

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