Nobody is saying that there's no tension on the wire, nobody is saying the tension doesn't change. Care to tell us all where that kinetic energy generated is being transferred to.
If I thought for a second that you would be capable of following the explanation, I'd give it, but given your apparent inability to comprehend fairly simple physics, I'm not going to bother. Your best bet would probably be some remedial classes of some kind to at least get you up to a high-school level of understanding.
More insults lol .I'm only asking you to show me where the kinetic energy generated is being transferred to. Here's an example so you can get your head around what a torque is & how it has a relationship with pivot point's
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Oh, nice, a video on gyroscopic precession! Well, that's close enough to being on-topic I suppose...
Ok, some pendulum basics, since it seems the bleedingly obvious needs to be pointed out: at it's starting position, a pendulum has no kinetic energy, but a certain amount of potential energy (depending on how high it is above it's "rest" position, and how much it weighs). As it swings down to the lowest point of it's swing, all this potential energy is converted into kinetic energy. As it is swinging up again to the other high point, the kinetic energy it had is converted back into potential energy, with a small amount having been lost along the way as heat and sound.
And a little more in-depth: the tension in the wire at the top of the swing is equal to the weight of the bob multiplied by the cosine of the angle the wire makes with the vertical (mg.cosθ). At the lowest point of the swing, the tension is equal to the weight of the bob, plus the mass of the bob multiplied by it's tangential velocity squared and divided by the length of the wire (mg+mv
2/r).
The tension always acts along the wire, as does the centripetal force. There is no torque in the system.