This question was asked and never answered. I do have an additional question to add. All this FE crap is based on what you see must be real right? So who can draw a map of FE? RE maps have been in existence for hundreds, some might speculate thousands, of years. All the early explorers who mapped the earth were all wrong?

C-Ray you are on to something my man.

http://en.wikipedia.org/wiki/Spherical_Earth There are several reasonable ways to approximate Earth's shape as a sphere. Each preserves a different feature of the true Earth in order to compute the radius of the spherical model. All examples in this section assume the WGS 84 datum, with an equatorial radius "a" of 6,378.137 km and a polar radius "b" of 6,356.752 km. A sphere being a gross approximation of the spheroid, which itself is an approximation of the geoid, units are given here in kilometers rather than the millimeter resolution appropriate for geodesy.

* Preserve the equatorial circumference. This is simplest, being a sphere with circumference identical to the equatorial circumference of the real Earth. Since the circumference is the same, so is the radius, at 6,378.137 km.

* Preserve the lengths of meridians. This requires an elliptic integral to find, given the polar and equatorial radii: \frac{2a}{\pi}\int_{0}^{\frac{\pi}{2}}\sqrt{\cos^2\phi + \frac{b^2}{a^2}\sin^2 \phi}\,d\phi. A sphere preserving the lengths of meridians has a rectifying radius of 6,367.449 km. This can be approximated using the elliptical quadratic mean: \sqrt{\frac{a^2+b^2}{2}}\,\!, about 6,367.454 km.

* Preserve the average circumference. As there are different ways to define an ellipsoid's average circumference (radius vs. arcradius/radius of curvature; elliptically fixed vs. ellipsoidally "fluid"; different integration intervals for quadrant-based geodetic circumferences), there is no definitive, "absolute average circumference". The ellipsoidal quadratic mean is one simple model: \sqrt{\frac{3a^2+b^2}{4}}\,\!, giving a spherical radius of 6,372.798 km.

* Preserve the surface area of the real Earth. This gives the authalic radius: \sqrt{\frac{a^2+\frac{ab^2}{\sqrt{a^2-b^2}}\ln{(\frac{a+\sqrt{a^2-b^2}}b)}}{2}}\,\!, or 6,371.007 km.

* Preserve the volume of the real Earth. This volumetric radius is computed as: \sqrt[3]{a^2b}, or 6,371.001 km.

Note that the authalic and volumetric spheres have radii that differ by less than 7 meters, yet both preserve important properties. Hence both, and occasionally an average of the two, are used.