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« **on:** December 15, 2008, 03:46:32 PM »
Rowbotham suggests that the "drop" at 6 miles would be over 20ft. My calculations show that to be way off.

Suppose that the earth is a sphere of radius 3963 miles. If you are at a point P on the earth's surface and move tangent to the surface a distance of 1 mile then you can form a right angled triangel as in the diagram. Using the theorem of Pythagoras a2 = 39632 + 12 = 15705370 and thus a = 3963.000126 miles. Thus your position is 3963.000126 - 3963 = 0.000126 miles above the surface of the earth. 0.000126 miles = 12*5280*0.000126 = 7.98 inches. Hence the earth's surface curves at approximately 8 inches per mile.

Now, this could explain some of what he is saying about restoring hulls with a telescope. His distances are all wrong and he concludes that you can see hulls at 6 miles.

What are your thoughts about this?