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**Flat Earth Believers / Re: Advanced Flat Earth Theory**

« **on:**November 13, 2023, 08:06:15 AM »

**NEW WEIGHT FORMULA: W = VΔ, WHERE Δ = 9.86 x d (d = density) - 9 DEXTROROTATORY SUBQUARKS AND 1.36sc DENSITY OF CONNECTING LINES III**

There are 14 billion bosons (photons, bubbles of light) in a subquark. The number of the antibosons (bosons which produce more darkness/aether/stillness instead of light/ether/sound) is six times as much.

http://www.subtleenergies.com/ormus/oc/chaptr01.htm

"The six little bodies are arranged in two sets of three, forming two triangles that are not interchangeable. The lines in the diagram of the atom on the gaseous sub-plane, Fig. 1. are not lines of force, but show the two triangles; on a plane surface the interpenetration of the triangles cannot be clearly indicated. "

http://www.subtleenergies.com/ormus/oc/fig001.gif

Those are 30 - 60 - 90 triangles (ratio of the sides 1 - √3 - 2).

The atomic density number must be multiplied by π

^{2}: nine subquarks and the connecting tubes.

π

^{2}- 9 = 0.8696, for a sacred cubit of 0.63662 units.

With a sacred cubit of 0.63673 unit we get π

^{2}- 9 = √3/2 ~= 1.361sc.

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg1774536#msg1774536

"Estimating the distance between successive bubbles as about six times the width of a bubble..."

14 x 6 = 84 billion antibosons per subquark

84 is our old friend: 84sc = 53.4

Total density: π

^{2}

84 x √3/2 = 72.746, which is quite amazing.

The missing apex of the Gizeh pyramid measures exactly 286.1 sacred inches, or 7.27 meters.

Those additional 72.7 billion antibosons form the sides (tubes) of the triangles connecting the subquarks of the hydrogen atom.

2y + √3y + y = 72.7/2

y = 7.68

√3y = 26.6/2, where of course we recognize the five sacred ratios: 26.7 - 53.4 - 80 - 136.1 - 534.

Now we know where the √3/2 figure contribution to the 9.86 total density number comes from.

No one has ever asked a FE this question about the g-force: if you agree that the object placed on a flat surface is not subject to the g-force, then where does the 9.86 discrepancy figure come from? Now, this question can be answered.

Garuda, the Firebird, the only planet/comet which can orbit the Sun very closely:

https://zetatalk.com/teams/tteam34s.htm

https://zetatalk.com/index/sign1083.jpg

https://zetatalk.com/newsletr/issue737.jpg

The 3:18 image captured the Winged Disc, the prior and later images did not have this rare capture. Per Skymap, only the planet Mercury should be in the four o'clock position on that day, to the right of the Sun.

This is not Nibiru. Nibiru is associated with Canopus, Saturn (in Aquarius/Cygnus) and Mars.

Garuda of great splendour, enkindling all the points of the universe, that mighty being endued with strength, that bird capable of assuming at will any form, of going at will everywhere, and of calling to his aid at will any measure of energy. Effulgent like a heap of fire, he shone terribly. Of lustre equal to that of the fire at the end of the Yuga, his eyes were bright like the lightning-flash. And soon after birth, that bird grew in size and increasing his body ascended the skies. Fierce and vehemently roaring, he looked as terrible as second Ocean-fire. (Mahabharata)

In the Persian mythology, Garuda is Muespar.

Muspar (a fiery comet that loiters around the sun)