The Weyl-Ivanov formula can be derived using only our knowledge of the concept of the density of subquarks.

**W = VΔ, WHERE Δ = 9.86 x d (d = density) - 9 DEXTROROTATORY SUBQUARKS AND 1.36sc DENSITY OF CONNECTING LINES**For the antigravitational effects to be seen, we need to first fill the FA-MI boson interval, and then create the force necessary to either have the laevorotatory subquarks emit 5.34x9.86 times as much aether as before, or supply the 5.34x9.86 density number of subquarks from the telluric currents. That is, we need to increase the density of the laevorotatory subquarks: first we activate the FA-MI boson interval from an inertial state, then once we reach this barrier, supply the necessary L-subquarks (antigravitons) from an outside source.

FA-MI interval

http://www.subtleenergies.com/ormus/oc/chaptr01.htmBut in the three thicker wires of the atom there is a very slight difference. The seven bubbles no longer fit exactly under one another, as it were, if one looks along or through the wire endwise; in 100 "spirillae of the lowest order" there ought to be just 700 bubbles; so there are in the seven thinner, coloured wires, but in the three thicker wires there are 704. So the increase is at present 1 in 175. And the same curious little increase holds good in the relation of the different orders of spirillae, In the thinner wires exactly 7 spirillae of one order make 1 of the next higher order, so that 700 "b"s make exactly 100 "a"s and so on; but in the thicker wires 704 "b"s go to 100 '"a"s. and the same curious proportion all through.

Those extra bosons represent the FA-MI interval (the SI-DO interval is already activated). They only become active and start the antigravitational phenomenon (activated laevorotatory subquark or dextrorotatory subquark) if the barrier is reached.

That barrier has been described as the density of ether or the permeability constant:

https://www.gsjournal.net/Science-Journals/Research%20Papers-Gravity/Download/5263https://web.archive.org/web/20150424214535/http://bourabai.narod.ru/gorbatz/ether-e.pdfThe value of k can be derived experimentally, using capacitors.

Here is the Weyl-Ivanov formula:

https://arxiv.org/pdf/gr-qc/0502047 (page 10)

On page 6 an even more generalized formula is derived, where g

_{z} = G^1/2 x V.

At the Honda Institute, an equivalent formula was obtained using mkgs units:

http://www.ovaltech.ca/pdfss/Possibility_of_Strong_Coupling_Between_Electricity_and_Gravitation.pdfhttp://jnaudin.free.fr/lifters/musha/Musha.pdfThen, at g

_{z} = 2.86g the first results should be seen, as exemplified here:

https://cassiopaea.org/forum/threads/acoustic-levitation-from-baalbek-to-tibet.41632/Full antigravitational effects would be obtained at g

_{z} = 5.34g = 5.34x9.86.

The voltage can be calculated using Avogadro's number (kg - g - mole - Na - positron/volt conversions).

It is to be noted that positive electricity (bosons) flow through positrons (antigravitons) and not electrons (gravitons). Negative electricity (gravity) flows through electrons/gravitons.

Dextrorotatory subquarks can increase the weight of an object only if they pass through that object itself: the 5.34g density of subquarks forms a ball lightning torus/sphere around the object.

One amp is defined as 6.28 x 10^18 electrons per second.

https://testbook.com/question-answer/how-many-electrons-would-flow-in-one-second-throug--602e4e95081e47183bf7c1b01 volt is an EMF of 6.24 X 10^18 electrons.

The atomic mass unit (amu or simply u) is the 1/12 of the mass of a 12C atom. Avogadro's number (NA=6.022×10^23) is the number of atoms contained in 12 g of 12C.

To obtain the mass of 2 moles of water, we simply the number of moles by molar mass: 2 moles X [2(1) + 16]g/mole = 36 g. Note that to get the molar mass of a compound, we simply add up the masses of the individual atoms, so the molar mass of water is 18 g/mole.

https://www.chem21labs.com/labfiles/berea_gl09_lab.pdfAvogadro's number, number of units in one mole of any substance (defined as its molecular weight in grams), equal to 6.02214076 × 10^23. The units may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction (if any).

https://research.chalmers.se/publication/528592/file/528592_Fulltext.pdfhttps://physics.stackexchange.com/questions/4234/why-is-the-relationship-between-atomic-number-and-density-not-linearhttps://en.wikipedia.org/wiki/Number_densityhttps://royalsocietypublishing.org/doi/full/10.1098/rsta.2011.0176The atomic mass unit (amu or simply u) is the 1/12 of the mass of a 12C atom. Avogadro's number (NA=6.022×10^23) is the number of atoms contained in 12 g of 12C.

https://www.thoughtco.com/avogadros-number-example-chemistry-problem-609541https://bio.libretexts.org/Bookshelves/Microbiology/Microbiology_(Boundless)/02%3A_Chemistry/2.02%3A_Chemical_Bonds/2.2.04%3A_Avogadro's_Number_and_the_MoleAnother property of Avogadro’s number is that the mass of one mole of a substance is equal to that substance’s molecular weight.

The mass of an atom is determined by the number of protons and neutrons in the nucleus. It is usually expressed in atomic mass units (amu).

The atomic number density (N; atoms/cm3) is the number of atoms of a given type per unit volume (V; cm3) of the material.

helium - 2 pro 2 neu 2 ele = 18 + 18 + 2x18 where 2 Lsub and 1 Dsub in arrangement of three subqk

The atomic weight of a helium atom (4.002) is approximately four times that of an individual hydrogen atom (1.007), but since gaseous hydrogen is a diatomic molecule containing two hydrogen atoms (H2), helium gas is only twice as heavy as hydrogen gas.

The value of the mass number of hydrogen is 1, while the mass number of the helium is 4. Considering the mass number, the helium is four times heavier than that of the hydrogen element.

A helium atom is two times heavier than a hydrogen molecule.