# The Flat Earth Society

## Flat Earth Discussion Boards => Flat Earth Information Repository => Topic started by: wise on March 24, 2018, 01:44:17 PM

Title: Basic physics of flat earth theory: free or forced falling
Post by: wise on March 24, 2018, 01:44:17 PM
Free or forced falling:

We know there is a hypocritism in the globist theory about free falling. In the theory, the acceleration is indepent from the mass. But whenever an object lighter than the air falls, the theory collapses and turns to a mode considering the difference of masses. This is because, the general gravity formula is nothing but a hoax. In this working, we'll show how the formula of free falling is simple and no relevant something such as gravity hoax.

Free or forced falling in flat earth:

1- When two different objects goes inside themselves, the light one comes up by naturally.
2- the acceleration of a falling object is directly proportional to the difference in the weight of the objects moving within each other.
3- According to 1 and 2, the acceleration formula is:

a= K* (m1-m2)/m1

in this formula;

a= acceleration of heavier object.
K= constant
m1= heavier object
m2= lighter object; or environment which the falling object falls in. generally air or water.

This formula is valid in the air, water or in a vacuum space.

K can be calculated by numereous examples.

Calculating the constant of K

a=9,81 m/s^2 for general objects. So; we can calculate the K.

the mass of the air is: 1,225 kg/m3

An heavy object, iron has 7850 kg/m3

So;

9,81= K*(7850-1,225)/7850
>>
K= 9,811

So;

Formula turns to:

a= 9,811* ((m1-m2)/m1)^n

This formula is valid in the air, water, any liquids or gases and in the vacuum space.

There is a possibility of n to be different than 1. But we have not enough experiment let us calculate the n value. But as a good approach, 1 is fair enough for n value.

So;

universal free or forced falling formula;

a= 9,811* (m1-m2)/m1
Title: Re: Basic physics of flat earth theory: free or forced falling
Post by: wise on March 25, 2018, 12:25:52 PM
Theory:

Free falling accelerate in the air, any gases, water or any liquids is:

a= K* (m1-m2)/m1

Proof

When two object touch each other, perform themselves a force relevant with their masses.

F1= k*m1
F2= k*m2

Net force on m1 mass is:

Fnet = F1-F2

accelerate is dividing force to the mass. So that;

accelerate: a = (F1-F2)/m1

= (k*m1-k*m2)/m1

>> a=k*(m1-m2)/m1

Proven.

In this formula, k is calculated as 9,811 by many examples.

Examples

Any objects falls in the air:

Iron free falls in the air: a= 9,811*(7850-1,225)/7850= 9,81 m/s^2
Water/or human free falls in the air: a= 9,811*(1000-1,225)/1000= 9,799m/s^2
Any object equal to mass of air: a=9,811*(1,225-1,225)/1,225=0 (stops in the air)
An helium ballon (the weight of plastic material is neglected) a= 9,811*(0,169-1,225)/0,169= -61,30m/s^2 (to upward)

Helium actually has the potential to move up much faster. but this speed will decrease as the balloon plastic material aggravates the balloon.

Any objects falls in the water:

Iron free falls in the water: a=9,811*(7850-1000)/7850= 8,56 m/s^2
Human free falls in the water: a= 9,811*(990-1000)/990= - 0.10 m/s^2
-0,10 means 10 decimeter upward per a second. This is not so much. So that, a person's swimming or sinking in water is proportional to the body mass index; water ripple or water stream.
Wood free falls in the water: a=9,811*(550-1000)/550= -8,03m/s^2 (a wood never shrinks in the water)

The steps of theory, proof and examples is completed.
Title: Re: Basic physics of flat earth theory: free or forced falling
Post by: JQKAndrei on May 08, 2018, 12:24:11 AM
Theory is a pretty big word here and all we see are numbers.

Before calling it a theory you have to make sure these formulas work, always, with very small, small, big and very big objects. Then maybe you can call it a theory. Not an universal one though.

By the way, what do you define as "up"?
What's the connection between a heavier object and a lighter one?
Why would obe "fall" into another?
Where did you get 9.811 from?
Title: Re: Basic physics of flat earth theory: free or forced falling
Post by: sandokhan on May 08, 2018, 06:17:43 AM
Buoyancy, the upward force exerted by a fluid or using a lifting gas, that, we are told, opposes the weight of the object immersed in it.

(https://wikimedia.org/api/rest_v1/media/math/render/svg/1894cb9c15cec95d8b75d72de800db1da6f04d2a)

density of the fluid
volume of the displaced body of liquid
g force on location

(https://wikimedia.org/api/rest_v1/media/math/render/svg/9acf3dc4f1a54e2227f5ea4404209a086116e9c2)

Then, a similar formula can be derived which features the density (exemplifed in the calculations themselves) instead of the mass.

However, this formula is valid for objects immersed in fluids or for aerostats.

What is needed is a formula for objects immersed in ETHER:

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2034438#msg2034438

Title: Re: Basic physics of flat earth theory: free or forced falling
Post by: wise on December 27, 2018, 02:24:11 AM
Buoyancy, the upward force exerted by a fluid or using a lifting gas, that, we are told, opposes the weight of the object immersed in it.

(https://wikimedia.org/api/rest_v1/media/math/render/svg/1894cb9c15cec95d8b75d72de800db1da6f04d2a)

density of the fluid
volume of the displaced body of liquid
g force on location

(https://wikimedia.org/api/rest_v1/media/math/render/svg/9acf3dc4f1a54e2227f5ea4404209a086116e9c2)

Then, a similar formula can be derived which features the density (exemplifed in the calculations themselves) instead of the mass.

However, this formula is valid for objects immersed in fluids or for aerostats.

What is needed is a formula for objects immersed in ETHER:

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2034438#msg2034438

Sorry.

g force on location is undefined. So that your formulas are not understandable. Please do not use undefined strange terms in formulas.