You can throw a tennis ball to a friend on a moving train and it will behave as if the train is still.
Now try doing it when the train is going around in a circle, the ball will always end up to the left of where it should have landed.
In physics when something travels in a circular path it's angular velocity is constantly changing. The object may have a constant speed but it is constantly changing direction to get a circular path.
Going around a corner in a car at a constant speed still makes the passengers move to one side.
So if the earth is circling the sun it's angular velocity should be constantly changing so we should feel it
There should be an experiment available to measure this if it's real.
Is there?
You can throw a tennis ball to a friend on a moving train and it will behave as if the train is still.
Now try doing it when the train is going around in a circle, the ball will always end up to the left of where it should have landed.
In physics when something travels in a circular path it's angular velocity is constantly changing. The object may have a constant speed but it is constantly changing direction to get a circular path.
Going around a corner in a car at a constant speed still makes the passengers move to one side.
So if the earth is circling the sun it's angular velocity should be constantly changing so we should feel itNo.
That's a fine answer, but what exactly do you mean by:This is the difference in gravitational force from the Sun depending on whether you're on the side of Earth facing it or facing away.
"This means the weight of an average-size person weighing 700N at g0 (mass ~ 71.4 kg) would change from 700.42N at noon to 699.58N at midnight due to the acceleration of the Earth moving in its orbit. Would you expect to feel that?"
I don't think it's very clear.
He said the weight changes from noon to midnightRead his post. His point is that it's virtually unnoticeable. That's a tenth of a percent increase.
There should be an experiment to measure this
Maybe we can't feel it,but there should be an instrument to measure this difference
Maybe we can't feel it,but there should be an instrument to measure this difference
Maybe we can't feel it,but there should be an instrument to measure this difference
I believe there are a few problems with the idea of weight changing from night to day. Take the ISS for example, it is orbiting around the Earth in a constant free fall. The astronauts inside the station are also orbiting and in a constant free fall, both the astronauts and the station are accelerating towards the center of the Earth at somewhere around 0.9 G. The astronauts experience weightlessness, you can not weigh yourself on the space station, because they are in constant acceleration.
We are also orbiting the Sun. The Earth can be viewed as our space station, we as astronauts inside the station. We should experience weightlessness with regards to the Sun because we are in a constant free fall towards it.
So if the earth is circling the sun it's angular velocity should be constantly changing so we should feel itSure, the earth is orbiting the sun, but at an angular velocity of one revolution per year! Big deal.
In physics when something travels in a circular path it's velocity is constantly changing. The object may have a constant speed but it is constantly changing direction to get a circular path.
He said the weight changes from noon to midnight
There should be an experiment to measure this
I thought tides were due to the moon, not the earth going around the sun.
I thought tides were due to the moon, not the earth going around the sun.
I thought tides were due to the moon, not the earth going around the sun.
The ocean tides are mostly caused by the moon. The sun does have a tidal relationship with the Earth as well, but it is much smaller than the moons, around 3% of the moons.
Clarifying further, the moon itself causes high tides on the side of the earth which is facing it. The high tides on the side of earth facing away from the sun are caused primarily by centrifugal force of the earth-moon system as they revolve around a common center of mass.The moon's gravity pulls water from the "sides" of the earth towards it, sides meaning neither directly under the moon nor on the other side but around the "horizon" as viewed from the moon. On the opposite side it would be just pulling the water straight into the earth so it won't go anywhere. This, coupled with what uCantBeSerious pointed out, allows for the water on the other side of the moon to remain at high tide.
OK one round earther just said the sun is the primary reason for the tides
So if the earth is circling the sun it's angular velocity should be constantly changing so we should feel it
OK one round earther just said the sun is the primary reason for the tides and another says it's only 3%
How is this measured?
There must be a way of actually measuring the inertia of the earth orbiting the sun with an instrument
I just realised we cannot detect the force caused by the Earth rotating the Sun because the Earth is always at all times in free fall around the Sun. We are weightless with respect to the Sun regardless of whatever forces are applied to us by the moon or planets and so forth.
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You are right, to an extent. We can detect the gradient, because the side of the earth that is closer to the sun is more attracted to it. Same thing with the moon. The opposite happens on the other side. That's what causes the tides. Here's some more information: https://en.m.wikipedia.org/wiki/Tidal_force
I just realised we cannot detect the force caused by the Earth rotating the Sun because the Earth is always at all times in free fall around the Sun. We are weightless with respect to the Sun regardless of whatever forces are applied to us by the moon or planets and so forth.
You are right, to an extent. We can detect the gradient, because the side of the earth that is closer to the sun is more attracted to it. Same thing with the moon. The opposite happens on the other side. That's what causes the tides. Here's some more information: https://en.m.wikipedia.org/wiki/Tidal_force
I just realised we cannot detect the force caused by the Earth rotating the Sun because the Earth is always at all times in free fall around the Sun. We are weightless with respect to the Sun regardless of whatever forces are applied to us by the moon or planets and so forth.
You are right, to an extent. We can detect the gradient, because the side of the earth that is closer to the sun is more attracted to it. Same thing with the moon. The opposite happens on the other side. That's what causes the tides. Here's some more information: https://en.m.wikipedia.org/wiki/Tidal_force
I think i am simply right. We cannot detect the force that is flinging us off to one side, like in a fair ground ride because we are in free fall and by definition there are no detectable forces upon us whatsoever. Earlier I was thinking about the magnitude of this force and if it would be bigger than the tidal force of jupiter. I assume we cannot measure the tidal force of jupiter either even though it can be estimated.
I just realised we cannot detect the force caused by the Earth rotating the Sun because the Earth is always at all times in free fall around the Sun. We are weightless with respect to the Sun regardless of whatever forces are applied to us by the moon or planets and so forth.
You are right, to an extent. We can detect the gradient, because the side of the earth that is closer to the sun is more attracted to it. Same thing with the moon. The opposite happens on the other side. That's what causes the tides. Here's some more information: https://en.m.wikipedia.org/wiki/Tidal_force
I think i am simply right. We cannot detect the force that is flinging us off to one side, like in a fair ground ride because we are in free fall and by definition there are no detectable forces upon us whatsoever. Earlier I was thinking about the magnitude of this force and if it would be bigger than the tidal force of jupiter. I assume we cannot measure the tidal force of jupiter either even though it can be estimated.
I didn't say anything about Jupiter.
Anyway, you'd be right, if the gravitational acceleration didn't depend on the distance, or if we all lived on the centre of mass of the earth. Tidal forces are detectable, just not very powerful. But other than that, you're absolutely right, and it's something that many flat earthers seem to miss.
I just realised we cannot detect the force caused by the Earth rotating the Sun because the Earth is always at all times in free fall around the Sun. We are weightless with respect to the Sun regardless of whatever forces are applied to us by the moon or planets and so forth.
You are right, to an extent. We can detect the gradient, because the side of the earth that is closer to the sun is more attracted to it. Same thing with the moon. The opposite happens on the other side. That's what causes the tides. Here's some more information: https://en.m.wikipedia.org/wiki/Tidal_force
I think i am simply right. We cannot detect the force that is flinging us off to one side, like in a fair ground ride because we are in free fall and by definition there are no detectable forces upon us whatsoever. Earlier I was thinking about the magnitude of this force and if it would be bigger than the tidal force of jupiter. I assume we cannot measure the tidal force of jupiter either even though it can be estimated.
I didn't say anything about Jupiter.
Anyway, you'd be right, if the gravitational acceleration didn't depend on the distance, or if we all lived on the centre of mass of the earth. Tidal forces are detectable, just not very powerful. But other than that, you're absolutely right, and it's something that many flat earthers seem to miss.
Your answer to the question appears to be, we cannot measure the force your body experiences as Earth orbits the sun once per year, however going off on a tangent a bit, the Sun does create a tide on earth as Earth rotates about Earths axis once per day which can be measured.
we can detect the tidal forces.