The Flat Earth Society

Flat Earth Discussion Boards => Flat Earth General => Topic started by: Jadyyn on December 07, 2015, 05:43:32 AM

Title: Space Shuttle Columbia Disaster
Post by: Jadyyn on December 07, 2015, 05:43:32 AM
If there are no satellites/space shuttles, FEers, please explain the Space Shuttle Columbia Disaster:
(https://en.wikipedia.org/wiki/Space_Shuttle_Columbia_disaster (https://en.wikipedia.org/wiki/Space_Shuttle_Columbia_disaster))

One of MANY images/videos/eye-witness accounts of the shuttle breaking up over Texas:
(http://cbsnews1.cbsistatic.com/hub/i/2013/02/01/4bb73173-a645-11e2-a3f0-029118418759/Columbia_AP_promo.jpg)

The yellow-red in this radar image is the debris from the shuttle. It was NOT flying at some 600 mph (747 aircraft). Over Dallas, when they lost contact, it was traveling ~Mach 18; 200,000 ft above ground. Debris was scattered over 2000 square miles in E.TX alone (area around the left pink spot below).
(http://www.directionsmag.com/images/articles/shuttle/shuttle1.gif)
Title: Re: Space Shuttle Columbia Disaster
Post by: Son of Orospu on December 07, 2015, 06:09:12 AM
The shuttle did not blow up in orbit.  Air planes have also broken up within the atmosphere.  I don't see your point, and I feel like you are simply grasping at straws.  Perhaps you can build another straw man that actually has the resemblance to making sense?  Just a suggestion. 
Title: Re: Space Shuttle Columbia Disaster
Post by: sircool on December 07, 2015, 08:30:32 AM
What happened to the astronauts? I asssume they died or was that a part of the conspiracy?
Title: Re: Space Shuttle Columbia Disaster
Post by: TheEngineer on December 07, 2015, 09:33:46 PM
If there are no satellites/space shuttles,
I'm pretty sure the Space Shuttle exists.  Especially since I've seen one.
Title: Re: Space Shuttle Columbia Disaster
Post by: sircool on December 08, 2015, 04:51:34 AM
If there are no satellites/space shuttles,
I'm pretty sure the Space Shuttle exists.  Especially since I've seen one.

How can you be so sure your eyes and your mind weren't playing tricks on you?
Title: Re: Space Shuttle Columbia Disaster
Post by: kido.resuri on December 08, 2015, 11:15:02 AM
The existence of ISS, space shuttles, or anything "orbiting" the Earth doesn't prove the shape or anything. There are balloons "orbting" high, if they were huge, you would be able to see them with telescopes as you can see the ISS. If it moves above you it doesn't mean it's "orbiting"...
Title: Re: Space Shuttle Columbia Disaster
Post by: sircool on December 08, 2015, 11:19:03 AM
The existence of ISS, space shuttles, or anything "orbiting" the Earth doesn't prove the shape or anything. There are balloons "orbting" high, if they were huge, you would be able to see them with telescopes as you can see the ISS. If it moves above you it doesn't mean it's "orbiting"...

I have never seen a balloon reach orbital speed! where can I observe this madness? :)
Title: Re: Space Shuttle Columbia Disaster
Post by: kido.resuri on December 08, 2015, 11:38:57 AM
Don't start arguing about something I didn't say.

By the way, can you measure that "orbital speed"? Can you measure it's height?
Title: Re: Space Shuttle Columbia Disaster
Post by: Master_Evar on December 09, 2015, 01:23:34 AM
Yes, you CAN:
But, I'll still give you the original equation :

D(ISS Orbit)=2H+8000miles

O(ISS Orbit)=[pi](2H+8000)miles

D(Earth)= 8000miles

H(ISS height over earth)=H

t(Time spent in 20 of your field of view straight overhead)  (variable)  (in seconds)

T(Time for ISS to make one full lap in orbit)=5400s

S(Length ISS travel along 20 of your field of view straight overhead)=2*H*tan(10)miles  (Using trigonometry, since this is only an approxmation and the arc is pretty small)=0.3527Hmiles  (roughly)

t/T=S/D(ISS Orbit) -> ts/5400s=0.3527Hmiles/[pi](2H+8000)miles  (equability)

t/5400=0.3527H/[pi](2H+8000)

t=0.3527H*5400/[pi](2H+8000)=1904.3H/[pi](2H+8000)

t[pi](2H+8000)=1904.3H

t[pi]2H+t[pi]8000=1904.3H

1904.3H-t[pi]2H=t[pi]8000

H(1904.3-2t[pi])=t[pi]8000

H=t[pi]8000/(1904.3-2t[pi])

Actually, it seems like something went wrong when I posted the equation in the earlier post, as it seems to be missing a number 2. I will edit that one quickly. This equation will only give you an approximation, as you can only approximate 20 of your FOV, approximate the time it travels and because it is doesn't take the curvature into account. But it is close enough to calculate if it is in space or not.

EDIT:

Almost forgot:

D=Diameter

O=Circumference

H=Height

S=Straight

t and T=Time

And then you can calculate the orbital speed by taking circumference and divide by orbital time (90 minutes or 5400 seconds)
Title: Re: Space Shuttle Columbia Disaster
Post by: sircool on December 12, 2015, 05:29:28 PM
Yes, you CAN:
But, I'll still give you the original equation :

D(ISS Orbit)=2H+8000miles

O(ISS Orbit)=[pi](2H+8000)miles

D(Earth)= 8000miles

H(ISS height over earth)=H

t(Time spent in 20 of your field of view straight overhead)  (variable)  (in seconds)

T(Time for ISS to make one full lap in orbit)=5400s

S(Length ISS travel along 20 of your field of view straight overhead)=2*H*tan(10)miles  (Using trigonometry, since this is only an approxmation and the arc is pretty small)=0.3527Hmiles  (roughly)

t/T=S/D(ISS Orbit) -> ts/5400s=0.3527Hmiles/[pi](2H+8000)miles  (equability)

t/5400=0.3527H/[pi](2H+8000)

t=0.3527H*5400/[pi](2H+8000)=1904.3H/[pi](2H+8000)

t[pi](2H+8000)=1904.3H

t[pi]2H+t[pi]8000=1904.3H

1904.3H-t[pi]2H=t[pi]8000

H(1904.3-2t[pi])=t[pi]8000

H=t[pi]8000/(1904.3-2t[pi])

Actually, it seems like something went wrong when I posted the equation in the earlier post, as it seems to be missing a number 2. I will edit that one quickly. This equation will only give you an approximation, as you can only approximate 20 of your FOV, approximate the time it travels and because it is doesn't take the curvature into account. But it is close enough to calculate if it is in space or not.

EDIT:

Almost forgot:

D=Diameter

O=Circumference

H=Height

S=Straight

t and T=Time

And then you can calculate the orbital speed by taking circumference and divide by orbital time (90 minutes or 5400 seconds)

excellent!
Title: Re: Space Shuttle Columbia Disaster
Post by: nodnyl on December 14, 2015, 09:25:42 AM
Were you hugged as a child?
Title: Re: Space Shuttle Columbia Disaster
Post by: hoppy on December 14, 2015, 09:30:57 AM
Were you hugged as a child?
I think his " uncle" hugged him often.
Title: Re: Space Shuttle Columbia Disaster
Post by: Aman68 on December 14, 2015, 12:54:18 PM
I saw a Youtube video showing that all of those astronauts are still alive. Not claiming, just stating!
Title: Re: Space Shuttle Columbia Disaster
Post by: ronxyz on December 14, 2015, 01:40:29 PM
Toward the end before the shuttle was destroyed they were talking about the jets chasing them. Jets fly in the air so the shuttle was in the air.
Several people on the ground took pictures and video with low resolution non-telescopic lens cameras. The detail shown in the images shows the shuttle plane was flying at normal plane height not at the edge of space.
Because parts of the shuttle plane landed on the Bush ranch some speculation was made that it was a shoot down. The distribution of the wreckage was similar to that of a high altitude plane failure. At the time North Korea was blustering.
Title: Re: Space Shuttle Columbia Disaster
Post by: Heiwa on December 15, 2015, 12:13:36 PM
The Columbia disaster was just a staged space event among 100's and nobody got killed as usual. But it kept 100's of NASA con people employed for a while back then - http://heiwaco.com/moontravel.htm#CC (http://heiwaco.com/moontravel.htm#CC) . And the show just goes on and on.