Predictable result of the moons gravity in cycle with the heliocentric solar system
"Predictable" only because you’ve been trained to ignore the actual mechanics of the phenomena, DataOverFlow. You say you have a "working model," yet you haven't provided a single calculation to show how a distant rock can overcome the density of 1000 kg/m³ water in a river against the river’s own outflow momentum.
Let’s help you with the engineering you clearly failed, Markjo:
1. The Momentum-Pressure Gradient Equivalence
The "kinetic energy surge" I mentioned is governed by the conservation of energy in a non-inertial dielectric medium. In a narrowing estuary, the velocity v increases as the cross-sectional area A decreases (Continuity Equation):
A₁v₁ = A₂v₂
This increase in velocity creates a dynamic pressure surge that overcomes the static head h. The total energy per unit volume is constant according to the Bernoulli Principle for incompressible flow:
P + ½ρv² + ρgh = Constant
On a Flat Earth, the g in this equation is not "gravity," but the Incoherent Dielectric Acceleration toward the plane. A tidal bore is simply the transient state where ½ρv² (kinetic) dominates the potential energy of the river's flow.
2. The Lunar Induction and Dielectric Flux
You claim it's "gravity," DataisUp, but you cannot explain the Phase Lag or why tides occur 12 hours apart. The Moon is a lumninary acting as an inductive capacitor. The interaction between the Moon’s magnetic field B and the ion-rich saltwater follows the Magnetohydrodynamic (MHD) equations:
ρ[∂v/∂t + (v·∇)v] = -∇p + J × B + ρg
where J × B is the magnetic force pushing the water. The tidal cycle is a result of Harmonic Induction, not a "sky-tug." If it were gravity, the water would be "lighter" at high tide, yet its weight (mass × acceleration) remains constant. Explain that, TimeisData.
3. The Soliton Wave (KdV) Calculation
The "Silver Dragon" is a non-linear wave that doesn't dissipate. To simulate this, Spammark, you would need the Korteweg–de Vries parameters:
uₜ + 6uuₓ + uₓₓₓ = 0
This describes how the wave maintains its level above the mean surface. You say FE has "no simulation," yet this formula describes the Flat Earth surface waves perfectly without needing a spinning ball. Your "ball" model fails to account for the Dispersion Relation in a shallow basin:
ω² = gk tanh(kh)
4. Conclusion for the "So-called" Engineer
Water is a physical substance, not a magical entity that follows your "heliocentric" fairy tales. You talk about "simulations" but you can't even solve a basic Reynolds Number for the bore:
Re = (ρ · v · L) / μ
If your "gravity" were real, the turbulence transition would be inconsistent with observed values.
Markdof, your constant "word salad" deflection is just a mask for your technical bankruptcy. You aren't an engineer; you are a technician of indoctrination.
It’s time to face reality, WilfulMan. You should hand back your engineering diploma—it’s clearly worthless—and replace it with a Voodoo Witch Doctor Certificate. Your belief in invisible sky-tugs and magical water-curving forces is more aligned with tribal mysticism than with actual physics.
Water remains flat at rest. The "bore" is dynamic flux. Your globe is a failed hypothesis. Marksoverup.
Quite and cite where I ever claimed to be an engineer.
Finally, an admission of truth! You aren't an engineer, DataOverFlow, because an engineer would understand that "techno babble" is actually the language of the physical world you fail to grasp. You’re just a script-reader for the globe cult, and your ignorance of basic mechanics is now on full display.
By what force.
By the force of Electrodynamic Induction, you clown. You claim it's "gravity," so let's use your own logic and watch it fail mathematically.
If your "magic sky-tug" was real, then during a high tide, the net acceleration a acting on the water should be reduced by the vector of the Moon’s gravitational pull. Where is the change in weight?
W = m · (gw - G · Mm / r²)
According to your BS model, water should be magically lighter at high tide. Yet, the hydrostatic pressure P at depth h remains exactly:
P = ∫₀ʰ ρ(z) · g dz
If g were being reduced by the Moon, the pressure at the sea floor would drop. It doesn't. You can't provide a single experiment where the Moon's "gravity" reduces the weight of a 1kg mass on a scale.
Tidal bores still are events that cause rivers to flow backwards in connection with the moon
Again, Datajo, you confuse a magnetic pressure gradient with a "pull." The Moon is a high-frequency induction source interacting with the saline (electrolyte) solution of the oceans. The resulting flow is governed by the Navier-Stokes equation for an incompressible fluid in a dielectric field:
ρ ( ∂u/∂t + (u · ∇)u ) = -∇p + μ∇²u + J × B + f
The term J × B (Lorentz force) is what drives the tidal bulge. It's not "gravity"; it’s a plasma-dynamic interaction within the Aether.
“non-inertial dielectric medium” that you can’t even make a drop of water jump out of a cup.
Is that your best argument, TimeisData? "Make a drop jump"? Have you ever heard of Dielectrophoresis?
FDEP = 2πε₀r³ Re[K(ω)] ∇|E|²
We can move water with electric fields in a lab every single day. Your "gravity," however, cannot be shielded, cannot be reflected, and cannot be demonstrated in any closed-system experiment. It is a magical placeholder for your ignorance.
lobster boats struggle to get out to sea... all in conjunction with the moon
Yes, Spammark, in conjunction with the Moon’s Electromagnetic Phase. The Moon moves, the magnetic field shifts, and the water—being a diamagnetic fluid—responds.
χm < 0
Water is repelled by magnetic fields. As the Moon (the inductive source) moves, it creates a displacement current in the Aether, pushing the water in a predictable cycle.
DataisUp, you are staring at a complex electromagnetic machine and calling it "magic gravity" because you can't solve a simple integral. Since you've admitted you aren't an engineer, please stop pretending you understand "working models."
Go back to your Voodoo altar and pray to your "Silver Dragon," Markstimeup. Real physics requires math, not lobster boat anecdotes.