The Flat Earth Society

Flat Earth Discussion Boards => Flat Earth Debate => Topic started by: Dnuor Htrae on June 08, 2009, 07:37:15 PM

Title: Antarctic Circumference?
Post by: Dnuor Htrae on June 08, 2009, 07:37:15 PM

The circumference of Antarctica is roughly 70,000 miles?
The FES should try telling that to competitors in the Antarctica Cup Yacht Race...
http://www.antarcticacup.com/x_maps.cfm (http://www.antarcticacup.com/x_maps.cfm)
I'm sure they'd like to know they're actually traveling upward of 50,000 miles, instead of the plotted 14,600 miles.
 ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ;D ::) :o ;) :D :P

(http://i140.photobucket.com/albums/r36/Persistenxe/Flat_earth-1.png)

(http://www.antarcticacup.com/images/jan08-racetrack-zoom.jpg)

Title: Re: Antarctic Circumference?
Post by: parsec on June 08, 2009, 07:54:05 PM

http://theflatearthsociety.org/forum/index.php?action=search2;params=YWR2YW5jZWR8J3wwfCJ8YnJkfCd8MTB8InxzaG93X2NvbXBsZXRlfCd8fCJ8c3ViamVjdF9vbmx5fCd8fCJ8c29ydHwnfHJlbGV2YW5jZXwifHNvcnRfZGlyfCd8ZGVzY3wifHNlYXJjaHwnfEFudGFyY3RpY2EgQ3VwIFlhY2h0IFJhY2U= (http://theflatearthsociety.org/forum/index.php?action=search2;params=YWR2YW5jZWR8J3wwfCJ8YnJkfCd8MTB8InxzaG93X2NvbXBsZXRlfCd8fCJ8c3ViamVjdF9vbmx5fCd8fCJ8c29ydHwnfHJlbGV2YW5jZXwifHNvcnRfZGlyfCd8ZGVzY3wifHNlYXJjaHwnfEFudGFyY3RpY2EgQ3VwIFlhY2h0IFJhY2U=)

Title: Re: Antarctic Circumference?
Post by: Dnuor Htrae on June 08, 2009, 08:06:14 PM

I counter with:
http://www.sailspeedrecords.com/index.php?option=com_content&view=article&id=53:wssr-newsletter-no-151-antarctica-cup-record-230508&catid=2:news&Itemid=5 (http://www.sailspeedrecords.com/index.php?option=com_content&view=article&id=53:wssr-newsletter-no-151-antarctica-cup-record-230508&catid=2:news&Itemid=5)
and
http://konyukhov.ru/eng/pressc/news/document3868.shtml (http://konyukhov.ru/eng/pressc/news/document3868.shtml)

Title: Re: Antarctic Circumference?
Post by: parsec on June 08, 2009, 08:11:28 PM

Third hit on Google searching Fedor Konyukhov:

http://www.ripoffreport.com/reports/0/196/RipOff0196150.htm (http://www.ripoffreport.com/reports/0/196/RipOff0196150.htm)

Title: Re: Antarctic Circumference?
Post by: Dnuor Htrae on June 08, 2009, 08:21:38 PM

Liar. It was the SECOND result.

Also, if you'd have read it, you'd know that the fraudulent charge in question is not that he finished the journey, but that he did not do it Solo as he had claimed. His yacht was allegedly so large that there were plenty of places to hide additional crew members.

The headline:

Quote

Fedor Konyukhov, Russian 'sportsman And Traveler' Mr. Konyukhov appears to be a fraud, who deceives his fans and audience. He imitates 'one-man' travels. Moscow Russian Federation

Title: Re: Antarctic Circumference?
Post by: parsec on June 08, 2009, 10:00:52 PM

Actually, the latitudes of the race are such that it cannot go out of the ring 45^o S and 60^o S. Apparently, the definition of the Southern Sea is south of parallel 60^o S. This gives a (-45^o) - (-60^o) = + 15^o = 15 x 60 = 900'. Knowing that one nautical mile corresponds to one arc minute along the meridian, this gives a corridor of width 900 nautical miles (this is clearly stated in the rules of the race (http://www.antarcticacup.com/x_maps.cfm)). The minimum length of the path is if they travelled along the southmost ring with radius (see figure below):

(http://img25.imageshack.us/img25/3320/lec3pic1.jpg)

r = R cos(-60^o) = R/2

This gives a circumference of:

s = 2 π r = π R

But, instead of using the radius of the Earth (a hypothetical quantity), let us relate it to the length of a meridian between the North Pole and the Equator L (This corresponds to an arc suspending an angle of 90^o = 90 x 60' = 5,400' or, by the definition of nautical miles 5,400 n. mi.). That would correspond to quarter of a circle with radius R on RE and would have a length:

L = R π/2  => R = 2 L/π

Substituting this in the above formula, we get:

s = 2 L

We now ask ourselves: What is the radius of a circle on a FE with this circumference. Obviously:

r = s/(2 π) = L/π = 5,400 n mi/3.14 = 1,720 n mi

This corresponds to a latitude that is 1,720' / 60 = 28.7^o south of the North Pole, or latitude of 61.3^o N.

I give you a point according to Google Maps that has this latitude:

http://maps.google.com/maps?f=d&source=s_d&saddr=61.3,+-44.121094&daddr=&hl=en&geocode=&mra=ls&sll=63.548552,-41.660156&sspn=10.021377,39.375&ie=UTF8&ll=62.915233,-150.46875&spn=92.291177,360&z=2 (http://maps.google.com/maps?f=d&source=s_d&saddr=61.3,+-44.121094&daddr=&hl=en&geocode=&mra=ls&sll=63.548552,-41.660156&sspn=10.021377,39.375&ie=UTF8&ll=62.915233,-150.46875&spn=92.291177,360&z=2)

Also, I give you these pictures:

(http://media.mcclatchydc.com/smedia/2007/12/10/16/46-10web-ENV-GREENLAND-MC.standalone.prod_affiliate.91.jpg)

(http://lineout.thestranger.com/files/2007/12/antarctica-summer-400.jpg)