The Flat Earth Society
Flat Earth Discussion Boards => Flat Earth Q&A => Topic started by: dgw on February 13, 2006, 03:26:52 PM
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OK lets assume the earth is flat and is moving upwards giving us 'gravity'. What makes the sun and the moon also move upwards so they appear at a constant distance from us? We can see the moon fairly clearly and from what I've read on other threads it is only 15 miles up, and I can't see anything on the bottom of the moon that's pushing it up.
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I think the question should be: Why do they stay up at all? And I'm pretty sure even FE thinks they are further out than 15 miles. After all, they are supposed to have a diameter of 32 miles. 15 miles is still within their radius.
I also don't think you'll get a proper answer. AFAIK, there's no mechanism in place to explain how the FE stars/planets/sun/moon stays above the flat earth, much less two discs hanging under it.
Wait, maybe that's it. Hanging from the ceiling. On some kind of tracks.
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I think 15 miles is supposed to be the distance to the surface of the moon, not to its center.
-Erasmus
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I'm sure they believe it's rushing up as a result of the same force pushing the earth.
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Right. And sometimes the forces pushes a little bit sideways, resulting in a closed orbit around the Earth. Epicycles, my friends, epicycles!
-Erasmus
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I think 15 miles is supposed to be the distance to the surface of the moon, not to its center.
-Erasmus
Ah. I stand corrected. My assumptions were somewhat incorrect anyway since they are not supposed to be spherical, and therefore the radius would not be in the way.
However, would not a 32-mile wide disc, 15 miles up in the sky, occupy about a quarter of the sky? If I recall correctly, both the sun and the moon occupy less than a 5 degree arc of the visual field.
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However, would not a 32-mile wide disc, 15 miles up in the sky, occupy about a quarter of the sky? If I recall correctly, both the sun and the moon occupy less than a 5 degree arc of the visual field.
Please hold while we compute....
We care about 2t, the angle the moon occuppies in the sky. Making a right triangle from {me, center-of-moon, edge-of-moon}, we see that tan(t) = 32/15 = 2.1333. Thus 2t is about 130 degrees.
The solid angle subtended by a cone with apex angle 2t is 2*pi*(1 - cos(t)) steradians -- thanks Wikipedia. So that's 2*pi*0.58, approximately, and the whole sky above the horizon is 2pi steradians. So the moon should, in this model, take up about 58% of the sky -- just over twice your estimate :)
-Erasmus
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Erasmus, remember, you can't use maths to disprove the Flat Earth theory, only to prove it.
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Erasmus, remember, you can't use maths to disprove the Flat Earth theory, only to prove it.
Doh!
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Erasmus, remember, you can't use maths to disprove the Flat Earth theory, only to prove it.
thats a sham lol
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Actually, according to the Johnson article, they're 3000 miles away? Maybe the Johnson model is different from the one mentioned in this thread.