In your supposed curvature,
The earth curves from dip of the horizon to the way the distances involved in battleship combat the horizon physically block ships from view bottom up.
Turning Torso (190m tall) - seen from 25km - 50km
The rate the building is blocked by the horizon is reasonable proof of earth’s curvature.
Part four, the classic. Ships disappearing bottom up.
During the video of “Turning Torso (190m tall) - seen from 25km - 50km”, the individual pans the camera across a near ship.
Then a ship farther away.
If that isn’t conclusive concerning the ship over the horizon. There is always my go to ship video.
Where the above shows the amount of curvature known as dip of the horizon can be measured
if you fired in a straight line,
One. You lie about the nature of the trajectory of ballistics. But if you had a magic bullet that didn’t drop because of gravity and could travel line of sight. You could still hit the portions of ship visible. Literally like line of sight communication. Where we know there is a dip to the horizon from radio and radar horizon.
Two. We been over the interaction of bullets and gravity. Higher velocity doesn’t change the drop rate of a fired bullet. A dropped bullet and a fired bullet drop towards earth at the same rate because of gravity and bullets are built to reduce drag and not shaped to create lift.
As for you guys who said all falling objects fall at the same rate...
Feather and Coin in a Vacuum (A8) [1C20.10]
Or like a dropped bullet falls at the same rate as a bullet fired from a muzzle.
Bullet Fired vs Bullet Dropped - Mythbusters for the Impatient
"we can't actually measure the speed of a bullet so we throw an absurd 1022 mph at it for a .22
I should read your posts more closely. I miss small easy to debunk items.
One. It’s pretty easy to tell if a bullet breaks the sound barrier.
Two.
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Where Bulma you lie about the heliocentric model.
The earth has a radius of 6378.1 kilometers.
If the earth was smooth. A scope .3 meters off the ground would still see about .6 meters of an object at 4km. Where only about .4 meters of the distance object hidden by curvature. That means at 4km, .6 meters of the object would be in straight line of sight.
Below is a simulation.
Poll