It is not my fault that you cannot understand that the angular size of the hull and mast decrease at a disparate rate because they converge at different rates.
I have already shown that the angular diameter of the hull is larger than is necessary for visibility under the given magnification, and you ignored these calculations.
Again-
If:
T1) If [there is nothing obscuring an object from view] then:
[Iff the angular diameter of an object is less than 1 arc second (2.909*10^-4 radians), that object is invisible.]
(This is Rowbotham's theorem.)
T2) The angular diameter of an object is about the object's height in radians divided by the distance to the object times the magnification of the lens used. (AD = (height)*(magnification)/(distance) )
Then:
L1) Let: the distance to the ship be 25 km.
h be the height of the part of the hull that is invisible (call this invisible object "IH")
magnification of the lens =10.
L2) By T2, an object viewed through a 10x lens at 25 km will have an angular diameter of 1 arc second or greater iff the object's height, y satisfies y ≥ (distance)*(AD)/(magnification) = 25000*2.909*10^-4 / 10 = 0.727 m.
L3) h ≥ .727 m by inspection of the photo taken from a high position. By L2, IH has an angular diameter of 1 arc second or greater.
L4) By L3 and T1, since IH is invisible and IH has an angular diameter of 1 arc second or greater, IH must be obscured by something. This is zetetically observed to be water.
L5) By L4, the water demonstrates curvature, which is indicative of an RE.
That is all. If you wish to argue, please point to the line you believe is in error.