Why doesn't rain experience coriolis effect as it falling down to the earth. Eventhough it is come from altitude with higher linear velocity than earth surface or athmosphere layer below from where it come (as the earth rotating). So rain must travel in a slightly deflected path to the earth surface.
Have you done the calculation to determine what effect it would have?
Lets make a few assumptions to simplify. Earth rotates exactly once every 24 hours. The rain can fall from 10 km altitude, directly over the equator, (r=6378.1 km) and not be affected by the wind (so it starts falling straight "down" and the sideways velocity from the Coriolis effect isn't cancelled.
Well, at the equator, Earth with the surface travelling at a velocity of ~463.8 m/s.
To keep the cloud moving with Earth, it is going to have to travel at ~464.6 m/s.
This is a difference of only 0.73 m/s.
That means with a raindrop falling down, if it wasn't affected by the wind (which it is, as it is going at or near terminal velocity), it would have a
sideways velocity of 0.73 m/s.
As we are assuming it isn't being affected by wind, that would mean it doesn't reach terminal velocity and instead just keeps speeding up.
A fall of 10 km would give it a velocity of (assuming a downwards acceleration of ~9.78 m/s) of ~442 m/s.
This means it would fall at an angle of ~0.1 degrees, or nothing significant.
But rain never reaches that velocity as it has too large a surface area to volume ratio.
Assuming it is falling at 10 m/s, that puts it at an angle of 4 degrees from vertical. Not much, and the horizontal velocity would also be significantly reduced.
The smaller you make your raindrops, to slow their velocity, the more they would be affected by wind, and thus the less of that change in velocity would carry through.
Then you need to throw in wind as well. I have seen rain coming in almost sideways due to the wind.
You simply aren't going to be able to notice the insignificant Coriolis effect here.