Ok you Flat Earth Deniers, you have been proven wrong once and for all unless you can draw me a Free Body Diagram of an Airplane that is land on the airport of Tel Nov Air Base in Tel-nof, Israel.
Here is the information:
An airplane, takes off from the airport of Svalbard in Longyear, Norway. This is a real airport where in 2014 154,261 passengers used it. It is has a Latitude of 78.246111 Degrees and a Longitude of 15.465556 Degrees. It’s symbol is “LYR”. The runway is 2,483 meters long and is made of asphalt. It is facing East to West with an angle of 16.4 degrees from the horizontal axis.
The airplane travels to the airport of Tel Nov Air Base which is located in Tel-nof, Israel. This is also a real military airport of the Israeli air force. It is has a Latitude of 31.839472 Degrees and a Longitude of 34.821844 Degrees. It’s symbol is “LLEK”. The runway is 2,402 meters long and it is made of asphalt. It is facing North to South with an angle of 3.24 degrees from the vertical axis.
The distance that the airplane traveled is 5,251.2 km
The airbus A330-200 has a range of 13,450 km so the distance is realistic.
Know if the earth is a sphere and it spins, that means that at the equator is 40,075 km. It needs 24 hour a rotation which means that its speed is 1,670 km/hr or 463 m/s.
Velocity = angular velocity * radius.
If the radius of the earth is 6,371 km or 6,371,000 m
Then the angular velocity of the earth is 463 / 6,371,000 => 7.267 x 10^-5
The velocity in a specific location on the earth is the (angular velocity of the earth) * (the radius from the spin axis)
The radius of the spin axis can be calculated from trigonometry with the formula
cos(θ) = value / (earths radius)
So for Svalbard Airport with a latitude of 78.246111 degrees,
value = (earth radius) * cos (78.246111) = 6,371,000 m * cos (78.246111)
value = 1,297,825 m
and the velocity at that point will be
Velocity = 7.267 x 10^-5 * 1,297,825 m = 94.31 m/s
At the Tel Nov Air Base, if you do the same math, you will get
Velocity = 393.33 m/s.
So you are traveling from a location that will have a smaller ground velocity and thus a smaller inertia force which just so happens to be in the direction that the airplane is taking off and you are landing in a location where the ground velocity is much greater in a direction which is perpendicular to the earth rotation.
Now show me your free body diagram of the airplane landing and label all the forces on the airplane and show me the forces that synchronize the airplane with the ground speed. The airplane is landing perpendicular to the earths rotation.
Either show me the forces or admit that the earth is stationary!!!!!
I would like to wise a nice day to the wolf pack of heliocentric priests.