Under FET how do parachutes work?

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Under FET how do parachutes work?
« on: January 17, 2010, 03:16:13 PM »
Heres one for you, if we assume gravity then the theory behind parachutes works perfectly fine, given that I am falling and the parachute helps to slow my rate of descent, but if we assume FET and the UA then how could me having a parachute possibly affect the rate at which the ground is accelerating up towards me, surely it's accelerating at the same speed whether I have a parachute or not!!

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Crustinator

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Re: Under FET how do parachutes work?
« Reply #1 on: January 17, 2010, 03:22:26 PM »
Heres one for you, if we assume gravity then the theory behind parachutes works perfectly fine, given that I am falling and the parachute helps to slow my rate of descent, but if we assume FET and the UA then how could me having a parachute possibly affect the rate at which the ground is accelerating up towards me, surely it's accelerating at the same speed whether I have a parachute or not!!

Because your descent is limited by drag.

And because acceleration and gravity are locally indistinguishable.

Also FET assumes that its world is capable of containing an atmosphere.

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Lord Wilmore

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Re: Under FET how do parachutes work?
« Reply #2 on: January 17, 2010, 05:48:16 PM »
Moved to Q&A.
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Johannes

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Re: Under FET how do parachutes work?
« Reply #3 on: January 17, 2010, 10:27:37 PM »
The acceleration of the earth due to UA and your "theoretical" acceleration due to gravity are the same.

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Mookie89

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Re: Under FET how do parachutes work?
« Reply #4 on: January 17, 2010, 11:16:22 PM »
In the FE model, he Earth pushes the atmosphere up with it, so the atmosphere that is pushing against your parachute, slows your rate of descent.
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Parsifal

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Re: Under FET how do parachutes work?
« Reply #5 on: January 18, 2010, 05:09:38 AM »
Same way they do in RET.
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spanner34.5

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Re: Under FET how do parachutes work?
« Reply #6 on: January 18, 2010, 06:51:22 AM »

A:   Parachutes work because of something called ‘air resistance.’ If there were no air resistance, then gravity would cause everything to fall at the same rate, so no matter what item you dropped (i.e. a feather or a rock), it would hit the ground at exactly the same time (assuming you dropped it from the same height). But air resistance complicates things (and makes sky-diving a lot more fun). Air resistance happens because as things fall, they have to push their way past the atoms and molecules that make up air in order to get where they’re going.

For something like a rock, this isn’t really a big deal, since rocks tend to be really heavy while being pretty small, so they can push the air molecules out of the way quite easily. But things like feathers can’t push the air molecules out of the way very well – for one, they weigh less so they don’t push as hard. And for another, they’re pretty big, so they run into a lot more air molecules than the rock does. So the air actually slows the feather down.

This is what makes parachute work. If a person were to fall without a parachute, they’d push the air molecules out of the way very easily, so the air wouldn’t be able to do much to slow the person down. But if the person is attached to a parachute, then the parachute will run into lots of air molecules, and especially if it’s curved to be higher up in the middle, it will be very hard for the air molecules to get out of the way. If they can’t get out of the way, they will slow the parachute (and hence the person) down.


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Benjamin Franklin

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Re: Under FET how do parachutes work?
« Reply #7 on: January 18, 2010, 07:45:07 AM »
Einstein developed something called the "Equivalence Principle" that states that, on a local level, acceleration, like what the FET has, and gravitation, like what RET has, would be indistinguishable. That is, you couldn't tell one from the other.

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Crustinator

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Re: Under FET how do parachutes work?
« Reply #8 on: January 18, 2010, 10:25:55 AM »
Einstein developed something called the "Equivalence Principle" that states that, on a local level, acceleration, like what the FET has, and gravitation, like what RET has, would be indistinguishable. That is, you couldn't tell one from the other.

No need to resort to Einstein. Newton gave us exactly the same thing.